Question

∠C and ​ ∠D ​ are vertical angles with m∠C=−3x+58 and m∠D=x−2 . What is m∠D ?

Answer 1

Answer:

m<D is $13^{0}$

Step-by-step explanation:

Vertically opposite angles are said to be equal angles, thus;

                   m<C = m<D

So that,

              -3x + 58 = x -2

             -3x - x = -2 -58

               - 4x = - 60

                 x = $\frac{- 60}{- 4}$

                 x = 15

Thus,

  m< D = x - 2

           = 15 - 2

           = $13^{0}$

Therefore, m<D is $13^{0}$

Answer 2

Vertical angles are equal

-3x + 58 = x - 2
-3x - x = -2 - 58
-4x = - 60
x = -60/-4
x = 15

m < D = x - 2....15 - 2 = 13 <====
m < C = -3x + 58....-3(15) + 58 = 13