The reaction starts with Anisole which is ortho-para directing group. So reacting anisole with Con H2SO4 and con HNO3 gives paranitro anisole.
Now paranitro anisole is a meta directing group and having low electron density in meta position which on reacting with Cl2 and anh AlCl3 directs the chlorine to meta position of nitro group and results in formation of the product 2-chloro-4-nitroanisole.
Thus, the product is 2-chloro-4-nitroanisole
Answer:
2
b= they are grouped differently, but all the atoms are still there.
First of all you have to consider the teoric value of the antiacid in order to titrate with the appropriate concentration of acid, in this case HCl. For example, the teoric value of antiacid Al(OH)3 is 5mg. Then, we calculate the molarity of titrating solution:
0.005g x 1mol/78g x ![0.005g Al(OH)3x \frac{1molAl(OH)3}{78gAl(OH)3} x \frac{3molHCl}{1mol Al(OH)3} x \frac{1molHCl}{0.025L} = 7.69x10^-3 M](https://tex.z-dn.net/?f=0.005g%20Al%28OH%293x%20%5Cfrac%7B1molAl%28OH%293%7D%7B78gAl%28OH%293%7D%20x%20%5Cfrac%7B3molHCl%7D%7B1mol%20Al%28OH%293%7D%20x%20%5Cfrac%7B1molHCl%7D%7B0.025L%7D%20%3D%207.69x10%5E-3%20M)
-Prepare the HCl 2.56x10^-3 M solution with the solutions available in your laboratory.
-Take one tablet of antiacid and put it in an beaker of 500 ml.
-Add 100 ml of deionized water to the beaker
-Put a magnetic capsule stirrer and the flask on the magnetic plate
-Add two drops of acid base indicator corresponding to the pH equivalence point is. We will use methyl red which also, is suitable for a weak base strong acid titration.
- To perform the titration is important to rinse the burette with deionized water and then add some quantity of the titrant. Open the stopcock to drained up the content.
-Secure the burette with the clamp and fill the burette with the HCl 7.69x10^-3 M solution.
-Put the analite beaker underneath the burette.
-Start titration.
When looking down the groups the elements have an equal number of electrons in the outer shell. This means they react in a similar way making it easier for scientists to use.
Answer: longer wavelength and lower energy.
Explanation:
1) The wavelength is inversely related to the frequency. So, an electromagnetic wave with lower frequency will have longer wavelength.
This is the formula for electromagnetic waves:
λ = c / ν
where λ is the wavelength, c is the speed of light, and ν is the frequency.
2) Energy is directly related to the frequency.
This is the formula E = hν,
where E is the energy, h is Planck constant, and ν is the frequency.
So, the lower the frequency the lower the energy.
3) Conclusion:
<span>An electromagnetic wave that has a lower frequency than infrared radiation will have longer wavelength and lower energy than the infrared radiation</span>