Magma, if it's the picture I know of then it would be "C"
Answer:
Hexanol has the highest boiling point.
Explanation:
Boiling points of all give compounds are as follow,
Hexanol = 157 °C
Hexanal = 129 °C
Hexanone = 128 °C
Hexane = 68 °C
Types of Interactions found in these compounds are,
Hexanol = Hydrogen Bonding & London Dispersion Forces
Hexanal = Dipole-Dipole Interactions & London Dispersion Forces
Hexanone = Dipole-Dipole Interactions & London Dispersion Forces
Hexane = Only London Dispersion Forces
Strength of Intermolecular Forces:
Hydrogen forces are stronger than Dipole-Dipole Interactions, and Dipole-Dipole Interactions are stronger than London Dispersion Forces.
Result:
Hence, due to presence of strong Hydrogen Bond Interactions Hexanol has the highest Boiling Point.
Answer:- 0.88
Solution:- Masses of silver and copper metals are given and we are asked to calculate the percentage of silver in the alloy.
mass percent of Ag = 
Mass of Ag = 17.6 g
mass of Cu = 2.40 g
mass of alloy = 17.6 g + 2.40 g = 20.0 g
Let's plug in the values in the formula:
mass percentage of Ag = 
mass percentage of Ag = 88%
So, the mass percentage of silver in sterling silver is 88% and in decimal form it is 0.88.
The reaction mixture of problem 1 includes <span>10mL of 4.0 M acetone = 10 mL 1.0 M HCl = 10 mL 0.0050 M I2 = 20 mL H2O. if this is true then the procedure is the following:
In order to find the total volume of reaction then you need to do like this:
</span><span>V = 10 mL + 10 mL + 10 mL + 20 mL = 50 mL </span>
<span>[I2]o = (0.005 mol I2 / 1 L I2 solution) (10 mL I2 solution) / 50 mL = 0.001 M </span>
<span>To first order, the reaction rate is 0.001 M / 230 s = 4,3 e-6 M/s
Then if you want to find the rate yoe need to use the following formula:
</span><span> k [CO(CH3)2]^a [I2]^b [HCl]^c
</span>So: <span>4,3 e-6 = k (4 M * 10 mL / 50 mL)^a (1e-3 M)^b (1 M * 10 mL / 50 mL)^c
</span>
Answer:

Explanation:
(a) Hybridization of orbitals
See the Lewis structure of propyne in the first diagram below.
C1 is directly bonded to two other atoms (H and C2) so it is sp hybridized.
C2 is directly bonded to two other atoms (C1 and C3) so it is sp hybridized.
C3 is directly bonded to four other atoms (C2 and 3 H) so it is sp³ hybridized.
(b) C2-C3 Sigma Bond
See the atomic and molecular orbitals in the second picture below.
C3 is using its hybrid atomic orbitals to form sigma molecular bonds. The C2-C3 sigma bond is formed by the overlap of the C2 sp atomic orbital with the C3 sp³ atomic orbital to make a σ(sp-sp³) molecular orbital.
(c) Bond angles
C1 and C2 are sp hybridized. Since the angle between sp orbitals is 180°, all atoms directly attached the C1 and C2 must be in a straight line. The C-C-C bond angle is 180°.