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Rudik [331]
3 years ago
11

Era that we live in 1. precambrian time 2. mesozoic 3. paleozoic 4. cenozoic

Physics
1 answer:
guajiro [1.7K]3 years ago
8 0

I believe we live in the Cenozoic era

We live in the Holocene Epoch, of the Quaternary Period, in the Cenozoic Era (of the Phanerozoic Eon).

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Today, most classification systems place bacteria in the kingdom
ElenaW [278]

Answer:

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Explanation:

3 0
4 years ago
A 75 cm straight wire moves straight up through a 0.53 T magnetic field with a velocity of 16 m/s. What is the induced emf in th
Luden [163]

Answer:

Induced emf of the wire is 6.36 Volts.

Explanation:

It is given that,

Length of the wire, l = 75 cm = 0.75 m

Magnetic field, B = 0.53 T

Velocity, v = 16 m/s

The wire is moving straight up in the magnetic field. So, an emf is induced in the wire. It is given by :

\epsilon=Blv

\epsilon=0.53\ T\times 0.75\ m\times 16\ m/s

\epsilon=6.36\ V

So, the induced emf of the wire is 6.36 V. Hence, the correct option is (b) "6.36 V".

5 0
3 years ago
Read 2 more answers
A cylinder contains 3.0 L of oxygen at 310 K and 2.5 atm. The gas is heated, causing a piston in the cylinder to move outward. T
Alex_Xolod [135]

Answer:

The gas pressure is: 1.55 atm.

Explanation:

We need to use the equation that relate the variables given at the exercise (pressure, temperature and volume) from the ideal gas law formula, when the mass is constant we can reduce the expretion PV=nRT to \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2} } solving to P2 we get:\frac{P_{1}V_{1}T_{2}}{T_{1}V_{2}}=P_{2} replace the values P_{2}=\frac{2.5*3*610}{9.5*310} =1.55(atm).

5 0
3 years ago
Consider a satelite in a low altitude orbit around the Earth. The gravitational acceleration felt by the satelite is very close
likoan [24]

Answer:

The orbital speed of the satellite around the earth in other to remain in perfect circular orbit in given as:

v = sqrt[(Ge*M)/R],

where Ge is the gravitational constant (Ge = 6.673 x 10^-11N/m2/kg2), M is the mass of the earth(m = 5.98 x 10^24kg), and R is the radius of the earth (R = 6.47 x 10^6m)

v = SQRT [ (6.673 x 10^-11 N m2/kg2) • (5.98 x 10^24 kg) / (6.47 x 10^6 m) ]

v = 7.85 x 10^3 m/s

Explanation:

For a satelite in a low altitude orbit around the Earth, the gravitational force is the only force acting of the said satellite keeping it is a circular orbit. To keep this satellite in perfect circular orbit, it must be moving in at a certain speed, which is dependent on the earth mass and radius. This speed can be evaluated from the expression of centripetal force(F = mv2/r). The centripetal force Fc on the satellite is equal to the gravitational force on the satellite from the earth(Fe). That is, (Ge*M*m)/R2 = (m*v2)/R, where M is mass of the earth, and m is the mass of the satellite. making v the subject of the formula, the equation become v = sqrt[(Ge*M)/R].

4 0
3 years ago
What is the best definition of solar radiation?(giving brainliest)
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- Energy from the Sun that reaches the Earth
HOPE IT HELPS U!!!
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