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Rudik [331]
2 years ago
11

Era that we live in 1. precambrian time 2. mesozoic 3. paleozoic 4. cenozoic

Physics
1 answer:
guajiro [1.7K]2 years ago
8 0

I believe we live in the Cenozoic era

We live in the Holocene Epoch, of the Quaternary Period, in the Cenozoic Era (of the Phanerozoic Eon).

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Consider a coil lying in the plane of the screen and the external magnetic field pointing into the screen. As the external magne
Margaret [11]

Answer:

The direction of the induced magnetic field should be pointing towards the screen.

Explanation:

Because the magnetic field is decreasing, and if we use Len's law, the induced current will increase the external magnetic field. For this increase to occur, said magnetic field produced by the induced current must be pointing towards the screen.

6 0
3 years ago
Which of the following is true?
cluponka [151]

The moon and the Earth attract each other, with equal gravitational forces.

That may not sound too surprising.
But what do you think of THIS one:

-- You and the Earth attract each other, with equal gravitational forces.

-- Your weight on Earth is the same as the Earth's weight on you.


8 0
2 years ago
Read 2 more answers
1. A stone of mass 0.8 kg is attached to a 0.9 m long string. The string will break if the tension exceeds 60 N. The stone is wh
melamori03 [73]

Answer:

1. A. 8.22. m/s

Explanation:

7 0
2 years ago
A penguin slides at a constant velocity of 3.57 m/s down an icy incline. The incline slopes above the horizontal at an angle of
igomit [66]

Answer:t=0.81 s

Explanation:

Given

Penguin slides down with constant velocity of 3.57 m/s

as the Penguin Slides with constant velocity therefore F_{net} is zero on Penguin

F_{net}=mg\sin \theta -f_r

f_r=friction Force

f_r=\mu mg

\mu =coefficient of Kinetic friction

mg\sin \theta =\mu mg

\tan \theta =\mu

\mu =\tan 9.85=0.45

after reaching on floor final velocity of penguin will be zero after time t

thus

v=u+at

here a=\mu g

a=0.45\times 9.8=4.41  (deceleration)

0=3.57-4.41\times t

t=\frac{3.57}{4.41}=0.809

t=0.81 s

8 0
3 years ago
The massless spring of a spring gun has a force constant k=12~\text{N/cm}k=12 N/cm. When the gun is aimed vertically, a 15-g pro
ASHA 777 [7]

Answer:

0.011 m.

Explanation:

Energy stored in the spring = Energy of the projectile.

1/2ke² = mgh ................ Equation 1

Where k = spring constant, e = extension or compression, m = mass of the projectile, g = acceleration due to gravity, h = height.

make e the subject of the equation

e = √(2mgh/k)............................. Equation 2

Given: k = 12 N/cm = 1200 N/m, m = 15 g = 0.015 kg, h = 5.0 m

Constant: g = 9.8 m/s²

Substitute into equation 2

e = √(2×0.015×5/1200)

e = √(0.15/1200)

e = √(0.000125)

e = 0.011 m.

4 0
2 years ago
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