Ask question

Ask question

All categories

2 years ago

13

Find the total number of positive integers of 4 digits or less that can be taken from the digits 1, 2, 3, and 4 in the case that

a) repeating figures is not allowed b) repeat figures are allowed

1 answer:

Mars2501 [29]2 years ago

4 0

Answer:

1,2,4

Step-by-step explanation:

all are positive intergers

You might be interested in

HURRY HELP i need helppp

suter [353]

Answer:

that answe is b

Step-by-step explanation:

b because i took this test

7 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST!! PLEASE SHOW YOUR WORK!

LenKa [72]

Simplify:

Solution ===> −7 + 12 − 3(50 − 4(2 + 3)) =========> -85

= 5 − 3(50 − 4(2 + 3))

= 5 − 3(50 − (4)(5))

= 5 − 3(50 − 20)

= 5 − (3)(30)

= 5 − 90

= −85

Answer ================> -85

Simplify:

1/3 + 6(2/3 - 1/6)^2

1/3 + 6(1/2)^2

1/3 + 6(1/4)

1/3 + 3/2

Answer =======> 11/6 =========> Decimal =======> 1.833333.....

Hope that helps!!!! : )

5 0

3 years ago

For a school fundraiser, Elena will make pirate masks. She will order masks and print graphics on them. Elena must spend $349 on

SpyIntel [72]

Answer:

135 masks

Step-by-step explanation:

i hope my math is right lol

6 0

2 years ago

Read 2 more answers

How do I solve −5/6e−2/3e = −24

Luba_88 [7]

E=16 pls brainliest me have a good day/night

4 0

2 years ago

The length of each side of a square was decreased by 2 inches so the perimeter is now 49 inches. What was the original length of

aleksley [76]

The Original length of each side of square was 14.25 inches.

Step-by-step explanation:

Perimeter of a square is given by:

Perimeter = 4 * side

Let x be the original length of each side of square

So

decreasing 2 inch will mean

$x-2$

Perimeter of square after reducing 2 inches from each side

$4(x-2) = 49\\4x-8 = 49\\4x = 49+8\\4x = 57\\\frac{4x}{4} = \frac{57}{4}\\x = 14.25$

So,

The Original length of each side of square was 14.25 inches.

Keywords: Perimeter, square

Learn more about perimeter at:

#LearnwithBrainly

5 0

3 years ago