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balu736 [363]
2 years ago
9

Here is the histogram of a data distribution. All class widths are 1. Which of the following numbers is closest to the mean of t

his distribution?
A. 6
B. 9
C. 4
D. 3
E. 5

Mathematics
2 answers:
ozzi2 years ago
3 0

Answer:

The answer is A

It is 6 on apex

Alina [70]2 years ago
3 0

Answer: A. 6

Step-by-step explanation:

From the given histogram we got the following table of frequency distribution:-

X         f

1           5

2          4

3          4

4          1

5           1

7           5

8           4

9           4

10          5

Now, \sum f=5+4+4+1+1+4+4+5=28

\sum Xf=2\cdot5+3\cdot4+4\cdot4+5\cdot1+7\cdot1+8\cdot4+9\cdot4+10\cdot5=168

Now, \text{Mean=}\dfrac{\sum xf}{\sum f}=\dfrac{168}{28}=6

Hence, the mean of this distribution = 6

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Greatest to least is
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While -55 is a negative number
They all are rational number
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At a camp, kids can choose swimming, art, or music. 40 kids choose swimming, 16 choose art, and 24 choose music. What is the rat
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the ratio would be as follows

40:16

or

5:2

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10) Show that in a group of 10 people (where any two people are either friends or enemies), there are either three mutual friend
ddd [48]

Answer with explanation:

Number of People in the group =10 People

The combination between two people is that, they can be either friends or enemies.

Total number of Possible Relation

                            =18 +16+14+12+10+8+6+4+2

                            = 90 Relations in all.

Out of 90 relations , 45 will be friends and 45 will be enemies.

⇒Now, we have to prove that, between 10 people, there are either three mutual friends or four mutual enemies, and there are either three mutual enemies or four mutual friends.

→→If there are three mutual friends, total number of people in the group =3 ×2=6 people in the group

And, four mutual enemies in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual friends or four mutual enemies

   =6 +4

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Hence proved.

→→→→Second part is ,in this group there can be either three mutual enemies or four mutual friends.

⇒If there are three mutual enemies, total number of people in the group =3 ×2=6 people in the group

And, four mutual friends in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual enemies or four mutual enemies

   =6 +4

   =10

Hence proved.

3 0
3 years ago
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