Answer:
1 2/7
Step-by-step explanation:
Hi! so this is very easy to solve. Let me guide you through it!
6/7 divided by 2/3
Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.
Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes
6/7 X 3/2
For fraction multiplication, multiply the numerators and then multiply the denominators to get
6 x 3 18
__ ___ = ____
7 x2 24
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 18 and 14 using
GCF(18,14) = 2
18 ÷ 2 9
___ ___ = ___
14 ÷ 2 7
The fraction
9/7
is the same as
9÷7
Convert to a mixed number using
long division for 9 ÷ 7 = 1R2, so
9/7=1 2/7
so there fore =
6/7÷2/3=1 2/7
(sorrry this took long i was solving it!)
Answer:
x+2y=2
-1x+1y=5
Step-by-step explanation:
Any system whose equations have the following characteristic
x+2y=2
-1x+1y=1
Is equivalent to the original system, since the differ in a number, the first equation is divided by 2 and the second by 5, we can say any system is equivalent to the original when it is escalated by a factor between its functions.
Answer:
Step-by-step explanation:
I may get this wrong because I don't think it's clear enough.
3 Letters
The station call letters must start with 1 of 3 letters
3
The next letter must be one of 25 and the last letter is 24
3 * 25 * 24 = 1800
5 letters
3 * 25 * 24 * 23* 22 = 910800
Total 1800 + 910800 = 912600
Answer:
6000 in³
Step-by-step explanation:
To solve this problem, we simply have to find the volume of the shipping container that will be just enough to contain the 20 soda boxes.
To do this, we find the volume of each soda box and multiply it by the total number of soda boxes held by the shipping container.
Volume of the box = L * B * H
L = length = 15 in
B = breadth = 4 in
H = height = 5 in
V = 15 * 4 * 5 = 300 in³
This is the volume of each soda box.
The volume of 20 soda boxes will then be:
V = 20 * 300 = 6000 in³
This is the volume of 20 soda boxes and hence, the minimum size the shipping container can be.
