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otez555 [7]
2 years ago
7

Consider a single crystal of some hypothetical metal that has the FCC crystal structure and is oriented such that a tensile stre

ss is applied along a [112] direction. If slip occurs on a (111) plane and in a [011] direction, and the crystal yields at a stress of 5.12 MPa, compute the critical resolved shear stress.
Engineering
1 answer:
Naddik [55]2 years ago
5 0

Answer:

imma leabe

Explanation:

leabe leave*

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If i build thing a and thing a builds thing b did i build thing b
postnew [5]

Answer:

<h3>Yes</h3>

Explanation:

If you build thing "a" and thing "a" builds thing "b" you <u>indirectly</u> build thing "b".

3 0
3 years ago
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Five kg of water is contained in a piston-cylinder assembly, initially at 5 bar and 240°C. The water is slowly heated at constan
Digiron [165]

Answer:

The final temperature of water is 381.39  °C.

Explanation:

Given that

Mass of water = 5 kg

Heat transfer at constant pressure Q = 2960 KJ

Initial temperature = 240 °C

We know that heat transfer at constant pressure given as follows

Q=mC_p\Delta T

We know that for water

C_p=4.187\ \frac{KJ}{kg.K}

Lets take final temperature of water is T

So

Q=mC_p\Delta T

2960=5\times 4.187(T-240)

T=381.39  °C

So the final temperature of water is 381.39  °C.

7 0
2 years ago
HELP PLEASE!!!!
DaniilM [7]

Answer:

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8 0
2 years ago
Storm sewer backup causes your basement to flood at the steady rate of 1 in. of depth per hour. The basement floor area is 2600
Wittaler [7]

Answer:

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Explanation:

4 0
3 years ago
A 1 m3 rigid tank initially contains air whose density is 1.18kg/m3. The tank is connected to a high pressure supply line throug
Elanso [62]

To solve this problem it is necessary to apply the concepts related to density in relation to mass and volume for each of the states presented.

Density can be defined as

\rho = \frac{m}{V}

Where

m = Mass

V = Volume

For state one we know that

\rho_1 = \frac{m_1}{V}

m_1 = \rho_1 V

m_1 = 1.18*1

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For state two we have to

\rho_2 = \frac{m_2}{V}

m_2 = \rho_2 V

m_1 = 7.2*1

m_1 = 7.2Kg

Therefore the total change of mass would be

\Delta m = m_2-m_1

\Delta m = 7.2-1.18

\Delta m = 6.02Kg

Therefore the mass of air that has entered to the tank is 6.02Kg

5 0
2 years ago
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