Evaluate 343^4/3<br> 1. 7<br> 2. 49<br> 3. 2401<br> 4. Not a real number

a hobby shop has 4 times as many model airplanes as model helicopters. the total number of models is 35. how many model airplane

harkovskaia [24]

There are 8 airplanes...maybe...check me on a calculator....

5 0

4 years ago

Part C

Kay [80]

From the inscribed circle, AE and AD are the radius of the circle while BE and BD are the tangents.

<h3>What is an inscribed circle?</h3>

An inscribed circle simply means the largest circle that's contained in a triangle.

An inscribed circle touches its tangent to the three sides. In this case, AE and AD are the radius of the circle while BE and BD are the tangents. Also, angle ABE and ABD are 60°.

Learn more about inscribed circle on:

brainly.com/question/12199537

8 0

2 years ago

A new cream that advertises that it can reduce wrinkles and improve skin was subject to a recent study. A sample of 50 women ove

Harman [31]

Answer:

Option A is right.

Step-by-step explanation:

Given that a new cream that advertises that it can reduce wrinkles and improve skin was subject to a recent study. A sample of 50 women over the age of 50 used the new cream for 6 months. Of those 50 women, 44 of them reported skin improvement(as judged by a dermatologist)

$H_0: p=0.40\\H_a: p >0.40$

(Right tailed test)

Sample size = 50

Std error of proportion = $\sqrt{\frac{pq}{n} } \\=0.0693$

p difference= $\frac{44}{50} -0.40\\=0.48$

Z statistic = p diff/std error = 6.928

p value <0.00001

Since p is less than alpha, reject null hypothesis.

A. We can reject the null hypothesis that p=0.4 and accept that p>0.4. That is, the cream can improve the skin of more than 40% of women over 50.

4 0

4 years ago

A woman 5 ft tall walks at the rate of 7.5 ft/sec away from a streetlight that is 10 ft above the ground. At what rate is the ti

lesya [120]

Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.

8 0

3 years ago

Need help with these math questions

PSYCHO15rus [73]

$\sqrt{16-x}$ x = 8