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3 years ago

Determine which system below will produce infinitely many solutions. (2 points)

1 answer:

6 0

The only system that has infinitely many solutions is NUMBER 2. Where you solve a system, and both sides end up being 0=0, then the system will have infinitely many solutions. Well, in these four choices, Number 2 is the only one that ends up being 0=0 after I solved it.

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How do you write x^3/11 in radical form

valentinak56 [21]

Answer:

$\sqrt[11]{x^3}$

Step-by-step explanation:

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2 years ago

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What is negative 5 5/6–2 3/5

dangina [55]

Answer:

the answer is -8 13/30

Step-by-step explanation:

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3 years ago

(Before you answer I am looking for how I do it. I have the answers but I need to know an equation to do this instead of using l

Tema [17]

Answer:

14 and 16.

Step-by-step explanation:

We know that two consecutive even numbers is 30.

Let's let n be any number.

Then the first even number must be 2n.

This is because n can be any number, either even or odd. However, if we multiply it by 2, this ensures that 2n is even. Remember that any number multiplied by 2 yields an even number.

Therefore, the consecutive even number will be (2n+2). Not (2n+1), because that gives an odd number.

We know that they sum to 30. So, we can write the following equation.

$(2n)+(2n+2)=30$

And we solve from there:

$4n+2=30\\\Rightarrow4n=28\\\Rightarrow n=7$

So, the value of n is 7.

Therefore, the first even number is 7(2)=14.

And the consecutive even number is 16.

Edit: Typo

7 0

3 years ago

A circle has a diameter of 12 units, and its center lies on the x-axis. What could be the equation of the circle?

ycow [4]

Answer:

$x^{2} +y^{2} =36$

Step-by-step explanation:

A circle centered at (0,0) with radius r is $x^{2} +y^{2} =r^{2}$

Since your circle has diameter of 12, then its radius is 6. Then $r^{2} =36$

So a possible answer is: $x^{2} +y^{2} =36$

If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:

$(x+4)^{2} +y^{2} =36$

The center of this circle would be (-4, 0) which is still on the x-axis.

8 0

3 years ago

Find the value of x. A. 7 B. 9 C. 11 D. 12

Arisa [49]

Use the law of cosines to solve for angle A. Plug your known side length values into the equation a^2 = b^2 + c^2 – 2bc cos A.

Then use the law of sines to find angle B. (Sin A/a = Sin B/b = Sin C/c).

Because the two red angles within B are congruent, divide your angle measure in half.

From there, do the law of sines to solve for x. Good luck!

I hopes this helps

6 0

3 years ago

Read 2 more answers