Solution:
1) Add 80 to both sides
-np<60+80
2) Simplify 60+80 to 140
-np<140
3) Divide both sides by p
-n<\frac{140}{p}
4) Multiply both sides by -1
n>-\frac{140}{p}
Done!
B = {a, b, c, d}
C = {0, a, 2, b}
B ∪ C = {a, b, c, d, 0, 2}
<h3>Answer: E)</h3>
Everything from the set B and everything from the set C give to one set. Duplicated elements are written only once.
4 months because, 2 divided by 0.5 is 4 therefore she has been measuring the tree for 4 months
Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer:
y = 4x + 5
Step-by-step explanation:
anything with the slope of 4x is parallel to the given equation. therefore, there are an infinite amount of answers.
<u>so, y = 4x + any number</u>
hope this helps!<3
