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2 years ago

Part A: Solve −np − 80 < 60 for n. Show your work. (4 points)

1 answer:

7 0

Solution:

1) Add 80 to both sides
-np<60+80

2) Simplify 60+80 to 140
-np<140

3) Divide both sides by p
-n<\frac{140}{p}

4) Multiply both sides by -1
n>-\frac{140}{p}

Done!

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PLEASE HELP ME: the ratio of cars to trucks on a highway at any given time is 12 to 8. If there are always more than 105 cars on

andre [41]

Answer:

Step-by-step explanation:

First, set up the ratio of c:t, which is 12:8. Then set up your new ratio of c:t, which is 105:?. The way I find the easiest is to divide 105 by 12, which is 8.75, then multiply that by 8, which is 70. To check if it's right, just divide 12 by 8, and 105 by 70, and if they're the same number, you've got it right.

Ps. I'm guessing you meant to ask the minimum number of trucks, not cars.

5 0

2 years ago

Translate each question.<br> Four times the difference of a number and 7 is 32

schepotkina [342]

“Four times the difference of a number and 7 is 32”
Translation-
4(x-7)=32

6 0

2 years ago

If the width of a rectangle is(x + 5) cm and its perimeter is (10x + 26) cm.

zaharov [31]

Answer:

10x + 26 = 2x + 58

10x = 58-26

10x = 32

X = 3.2

I think??

3 0

2 years ago

The quotient of 365.085 and 79.8

Paul [167]

Answer:

4.575

Step-by-step explanation:

365.085/79.8=4.575

5 0

3 years ago

What is the area of this ^2

Ad libitum [116K]

<h2>Question:- Area of the given diagram</h2>

<h2>Answer :- </h2>

Divide the diagram as shown in attachment.

Now first calculate the area of the rectangle having side 1 and 12

So area = length ×breadth

Area = 1× 12 = 12 unit²

Now find the Area of the remaining triangle with sides 12,13,5 units

$Area = \frac{1}{2} \times base \times height \:$

Now put the value as -> base= 5 and height= 12

$Area = \frac{1}{2} \times base \times height \: \\ Area = \frac{1}{2} \times 5 \times 12 \\ Area = \frac{1}{ \cancel2} \times 5 \times \cancel{12}^{ \: \: 6} \\ Area = 5 \times 6 \\ Area = 30 \: units^{2}$

Now add both areas for your answer

$Area{ \tiny{1}} = 12 {units}^{2} \\ Area{ \tiny2} = 30 {units}^{2} \\ Area{ \tiny{total}} = Area{ \tiny{1}} + Area{ \tiny{2}} \\ Area{ \tiny{total}} = 12 + 30 = 42 {units}^{2}$

8 0

2 years ago