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lapo4ka [179]
3 years ago
7

TIMED

Chemistry
2 answers:
zhannawk [14.2K]3 years ago
6 0
Density = mass/volume
Density = 81g/0.9cm³
Density = 90g/cm³
: )
Arlecino [84]3 years ago
4 0

Answer : The density of the sample in grams per cubic centimeter is, 90g/cm^3

Solution : Given,

Mass of unknown sample = 81 g

Volume of unknown sample = 0.9cm^3

Formula used :

\text{Density of unknown sample}=\frac{\text{Mass of unknown sample}}{\text{Volume of unknown sample}}

Now put all the given values in this formula, we get the density of unknown sample.

\text{Density of unknown sample}=\frac{81g}{0.9cm^3}=90g/cm^3

Therefore, the density of the sample in grams per cubic centimeter is, 90g/cm^3

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The acid dissociation constant, ___, is a quantitative measure of acid strength
8090 [49]

Answer:

The acid dissociation constant, _Ka__, is a quantitative measure of acid strength

Explanation:

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3 years ago
If a carbon atom has -4 electrons
mixer [17]
Then it has lost 4 electrons meaning it is now positively charged
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4 years ago
10. A 2.36-gram sample of NaHCO3 was completely decomposed in an
Airida [17]

Answer:

0.79 g

Explanation:

Let's introduce a strategy needed to solve any similar problem like this:

  • Apply the mass conservation law (assuming that this reaction goes 100 % to completion): the total mass of the reactants should be equal to the total mass of the products.

Based on the mass conservation law, we need to identify the reactants first. Our only reactant is sodium bicarbonate, so the total mass of the reactants is:

m_r=m_{NaHCO_3}=2.36 g

We have two products formed, sodium carbonate and carbonic acid. This implies that the total mass of the products is:

m_p=m_{Na_2CO_3}+m_{H_2CO_3}

Apply the law of mass conservation:

m_r=m_p

Substitute the given variables:

m_{NaHCO_3}=m_{Na_2CO_3}+m_{H_2CO_3}

Rearrange for the mass of carbonic acid:

m_{H_2CO_3}=m_{NaHCO_3}-m_{Na_2CO_3}=2.36 g - 1.57 g=0.79 g

8 0
4 years ago
Which of the following ions is formed when a base is dissolved in a solution? H+ O− OH− SO42+
77julia77 [94]

Answer:

OH⁻

Explanation:

A base is defined as a substance which interacts with water to yield excess hydroxide ions, OH⁻, in an aqeous solution.

Examples are Sodium hydroxide (NaOH)

Potassium hydroxide (KOH)

Bases are generally certain metallic oxides, metallic hydroxides and aqueous ammonia.

An acid is a proton donor, H⁺ and it interacts with water to produce excess hydroxonium ions in an aqueous solution.

3 0
3 years ago
The Reynolds number, Re, is a dimensionless number used to characterize different flow regimes in a fluid. The Reynolds number c
Natalka [10]

Answer:

The aswer is Re= 1867.123

Explanation:

You know that Reynolds is:

Re=\frac{p*v*D}{u}

But the units of p, v, D and u must be in the same reference system. This means that you must handle the same units.  So, you must do the corresponding unit conversions . Usually The International System of Units is used, where:

the density p is measured in \frac{kg}{m^{3} } the velocity v in \frac{m}{s}, the diameter in m (meters) and the viscosity in \frac{kg}{m*s}

But you can choice other system of units.

The <em>density</em>, in this case, is expressed in \frac{kg}{m^{3} } ( Note that in the statement the data appears as kg / m. But remember that this isn't possible because density is the amount of mass in a given volume. You can assume that the given data is \frac{kg}{m^{3} }).  

For density then you shouldn't convert units, because it respects the International System of Units.

The <em>velocity </em>is expressed in \frac{cm}{s}. So, you must change these units to \frac{m}{s}. For that, The Rule of Three  is usually used, where it is known that 1 cm is 0.01 cm. So:

1 cm ⇒ 0.01 m

32.9 cm ⇒ x

x=\frac{32.9*0.01}{1}

Finally the velocity is: 0.329 \frac{m}{s}

In the same way, you can convert the units of the <em>diameter</em>.

1 cm ⇒ 0.01 m

1.85 cm ⇒ x

x=\frac{1.85*0.01}{1}

The diameter is: 0.0185 m

Finally, you must convert the <em>viscosity</em> units, applying The Rule of Three:

1 cP ⇒ 0.001 \frac{kg}{m.s}

3.40 cP ⇒ x

x=\frac{3.4*0.001}{1}

So, the viscosity is: 0.0034 \frac{kg}{m*s}

Now, with all units in the same system, you can <em>calculate the Reynolds </em>number.You just have to replace the numbers in the definition and verify that the Reynolds is a dimensionless number.

Re=\frac{p*v*D}{u} =\frac{1043*0.329*0.0185}{0.0034}

Re= 1867.123

<em>Unit Verification:</em>

Re=\frac{\frac{kg}{m^{3} } *\frac{m}{s}  *m}{\frac{kg}{m*s} }

By simple simplification, adimensionality can be observed.

7 0
4 years ago
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