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lapo4ka [179]
3 years ago
7

TIMED

Chemistry
2 answers:
zhannawk [14.2K]3 years ago
6 0
Density = mass/volume
Density = 81g/0.9cm³
Density = 90g/cm³
: )
Arlecino [84]3 years ago
4 0

Answer : The density of the sample in grams per cubic centimeter is, 90g/cm^3

Solution : Given,

Mass of unknown sample = 81 g

Volume of unknown sample = 0.9cm^3

Formula used :

\text{Density of unknown sample}=\frac{\text{Mass of unknown sample}}{\text{Volume of unknown sample}}

Now put all the given values in this formula, we get the density of unknown sample.

\text{Density of unknown sample}=\frac{81g}{0.9cm^3}=90g/cm^3

Therefore, the density of the sample in grams per cubic centimeter is, 90g/cm^3

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Determine the mass of 5.2 x 10 power of 21 molecules of propanol C3H7OH(l), on grams.
Alja [10]

n(\text{C}_3\text{H}_7\text{OH}) = N(\text{C}_3\text{H}_7\text{OH}) / N_A\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 5.2 \times 10^{21} / (6.02 \times 10^{23})\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 8.6 \times 10^{-3} \; \text{mol}

where N_A = 6.02 \times 10^{23}\; \text{mol}^{-1} the Avogadro's constant that relates the number of particles to their number, in the unit moles \text{mol}.

The molar mass of propanol- mass per mole propanol- can be directly deduced from its molecular formula with reference to a modern periodic table.

M(\text{C}_3\text{H}_7\text{OH}) = \underbrace{3 \times 12.01}_{\text{carbon}} + \underbrace{8 \times 1.008}_{\text{hydrogen}} + \underbrace{1\times 16.00}_{\text{oxygen}} = 60.09 \; \text{g} \cdot \text{mol}^{-1}

8.6 \times 10^{-3} \; \text{mol} of propanol molecules would thus have a mass of 8.6 \times 10^{-3} \; \text{mol} \times 60.09 \; \text{g} \cdot \text{mol}^{-1} = 0.52 \; \text{g}

5 0
3 years ago
Write the chemical equation for this reaction. Use the picture I provide!
Lesechka [4]

Answer:

H2O

H2O

Explanation:

because the are only two hydrogen that can react to Oxygen

3 0
2 years ago
Which of the following is the best description of a conversion table
kirill [66]
Can’t tell ya bc you didn’t list the answers
3 0
3 years ago
A atom has 20 electrons, 21 neutrons, and 20 protons. What is the atomic mass of the atom?
UNO [17]

name= calcium

atomic mass= 40.078 atomic mass unit

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5 0
3 years ago
The molar solubility of magnesium carbonate is 1.8 × 10–4 mol/l. What is ksp for this compound?
Serhud [2]

Answer:

3.2 × 10⁻⁸

Explanation:

Let's consider the solution of magnesium carbonate.

MgCO₃ ⇄ Mg²⁺(aq) + CO₃²⁻(aq)

We can relate the molar solubility (S) with the solubility product (Ksp) using an ICE chart.

         MgCO₃ ⇄ Mg²⁺(aq) + CO₃²⁻(aq)

I                             0                0

C                          +S              +S

E                            S                S

The Ksp is:

Ksp = [Mg²⁺] × [CO₃²⁻] = S × S = S² = (1.8 × 10⁻⁴)² = 3.2 × 10⁻⁸

4 0
4 years ago
Read 2 more answers
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