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lapo4ka [179]
3 years ago
7

TIMED

Chemistry
2 answers:
zhannawk [14.2K]3 years ago
6 0
Density = mass/volume
Density = 81g/0.9cm³
Density = 90g/cm³
: )
Arlecino [84]3 years ago
4 0

Answer : The density of the sample in grams per cubic centimeter is, 90g/cm^3

Solution : Given,

Mass of unknown sample = 81 g

Volume of unknown sample = 0.9cm^3

Formula used :

\text{Density of unknown sample}=\frac{\text{Mass of unknown sample}}{\text{Volume of unknown sample}}

Now put all the given values in this formula, we get the density of unknown sample.

\text{Density of unknown sample}=\frac{81g}{0.9cm^3}=90g/cm^3

Therefore, the density of the sample in grams per cubic centimeter is, 90g/cm^3

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Which of the following is not balanced?
White raven [17]
Is it asking which is or isn’t balanced
7 0
3 years ago
Why is one side of the moon called "the dark side of the moon"?
Lisa [10]

Answer:

Option C

Explanation:

The answer is option C or "The amount of time it takes to rotate around it's axis is the same amount of time it takes to revolve around Earth."Remember that the Earth and the Moons amount of time to make a full rotation is almost in sync and they're two sides of the moon, one side we do not see and that's because that side is currently faced away from the Earth which is called the dark side of the moon. Each side has two weeks oh night, and two weeks of day because of how long it takes the moon to revolve, so while we have a side towards the Earth which is illuminated by the sun we have another pointing away in the dark.

Hope this helps.

4 0
3 years ago
Describe an experiment to show that water contains hydrogen and oxygen only​
kondaur [170]

Answer:

Electrolysis

Explanation:

The electrolysis of water is one such experiment that shows that water is made up of hydrogen and oxygen atoms only in the ratio of 2 to 1.

In the electrolysis of water, electricity is passed through acidified water to cause it to decompose.

The electrolysis of water is also known as the electrolysis of dilute tetraoxosulphate  (VI) acid.

At the cathode, H⁺ ions are discharged and hydrogen gas is liberated:

               2H⁺       +     2e⁻     →        H₂

At the anode, both the sulfate ion and hydroxyl ions migrate to this electrode. Only the OH⁻ is selected for preferential discharge due to its lower position in that activity series.

         4OH⁻  →   2H₂O    +    O₂     +     4e⁻

Oxygen gas is produced at the anode.

This electrolysis demonstrates the volumetric composition of water that is, 2 volumes of hydrogen at the cathode and 1 volume of oxygen at the anode.

5 0
3 years ago
Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) + H2O (l) → Ca(OH)2 (s) In a p
dybincka [34]

Answer:

The option closest to the percentage yield is option;

d. 81.1

Explanation:

The given chemical equation of the reaction is presented as follows;

CaO (s) + H₂O (l) → Ca(OH)₂

The mass of CaO in the experiment, m = 2.00 g

The volume of water with which the CaO was reacted = Excess volume of water

Number of moles = Mass/(Molar mass)

The mass of Ca(OH)₂ recovered, actual yield = 2.14 g

The molar mass of CaO = 56.0774 g/mol

The number of moles of CaO in the reaction, n₁ = 2.00 g/(56.0774 g/mol ≈ 0.036 moles

The molar mass of Ca(OH)₂ = 74.093 g/mol

The number of moles of Ca(OH)₂ in the reaction, n₂ = 2.14 g/(74.093 g/mol) ≈ 0.029 moles

From the given chemical reaction, one mole of CaO reacts with one mole of H₂O to produce one mole of Ca(OH)₂

Therefore, 0.036 moles of CaO will produce 0.036 moles of Ca(OH)₂

Mass = Number of moles × Molar mass

The mass of 0.036 moles of Ca(OH)₂ ≈ 0.036 moles × 74.093 g/mol = 2.667348 grams

∴ The theoretical yield of Ca(OH)₂ = 2.667348 grams

Percentage \ yield = \dfrac{Actual \ yield}{Theoretical \ yield}  \times 100 \%

The percentage yield = (2.14 g)/(2.667348 grams) × 100 = 80.23%

Therefore, the option which is closest is option d. 81.1.

5 0
3 years ago
Which incorrect aspect of Rutherford’s model was fixed by Bohr’s model?
dolphi86 [110]

Answer:

Some things that were wrong with Rutherford's model were that the orbiting electrons should give off energy and eventually spiral down into the nucleus, making the atom collapse. Bohr proposed his quantized shell model of the atom to explain how electrons can have stable orbits around the nucleus. To remedy the stability problem, Bohr modified the Rutherford model by requiring that the electrons move in orbits of fixed size and energy.

Explanation:

7 0
3 years ago
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