The type of substances that would make good conductors would be substances that has greater density. This would mean that the particles of the substance are much closer to each other and would allow the free flow of the electrons in the substance. With this, current would be able to flow freely.
Answer:
neblua is a place for baby stars when they're born
Explanation:
a nebula is a gaseous cloud formed from dead stars. this works as a nursery for baby stars.
hope this helps:)
Answer:
Anode: H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻
Cathode: 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq)
E° = 1.60 V
Explanation:
Let's consider the reaction taking place in a galvanic cell.
2 Fe⁺³(aq) + H₂(g) + 2 OH⁻(aq) → 2 Fe⁺²(aq) + 2 H₂O(l)
The corresponding half-reactions are:
Anode (oxidation): H₂(g) + 2 OH⁻(aq) → 2 H₂O(l) + 2 e⁻ E°red = - 0.83 V
Cathode (reduction): 2 Fe⁺³(aq) + 2 e⁻ → 2 Fe⁺²(aq) E°red = 0.77 V
The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red, cat - E°red, an = 0.77 V - (-0.83 V) = 1.60 V
Hello!
The most stable isotope of Chromium is ⁵²Cr with a mass of 51,9405 amu.
We know that because of the information that we can find in the periodic table. Which information is that? The atomic weight of the element. Atomic weights are calculated taking into account the relative abundances of each isotope of the element. The isotope that is the most abundant one will influence more the atomic weight that is found in the periodic table.
For chromium, its atomic weight, that we can find on the periodic table, is 51,99 amu. The isotope weight that is nearest to this atomic weight is ⁵²Cr with a mass of 51,9405 amu, so that will be the most stable isotope.
Have a nice day!
Answer:
26.74g
Explanation:
The equation of the reaction is;
SIO₂ + 3C --> SiC +2CO
From the balanced equation, the relationship between SiC and C is;
3 mol of C produces 1 mol of SiC
Converting mol to mass using; Mass = moles * Molar mass
Mass of SiC = 1 mol * 40.11 g/mol = 40.11g
This means;
3 mol of C produces 40.11g of SiC
2 mol of C produces xg of SiC
3 = 40.11
2 = x
x = 2 * 40.11 / 3 = 26.74g
