Question

There are 15 members of the show choir. In how many ways can you arrange 4 members in the front row when order does not matter?

Answer 1

32760 ways. Because it is a permutation it would be 15!. Which is 15*14*13*12*11*10*9*8*7*6*5*4*3*2*1 

Answer 2

We need to find the number of combinations of the 15 members taken 4 at a time:
$15C4=\frac{15!}{4!11!}=\frac{15\times14\times13\times12}{4\times3\times2\times1}=1365$