Hello!
First you have to get the equation into slope-intercept form
Slope-intercept form is y = mx + b
-2x + 4y = -8
Add 2x to both sides
4y = 2x - 8
Divide both sides by 4
y = 1/2 x - 2
The graph is a line that goes through the points (0, -2), (-2, -3), (2, -1) and
(4, 0)
Hope this helps!
Answer:
Oook, quick setup: pick a cartesian plane, be 
the position of the helicopter as time passes, and 
your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need, in general what you want is to move one end of the segment up, the other right, and stretch it.
That distance is easily found with the formula for the distance between two points in the plane, or 
(playing a bit with the squares). At this point we need to write down expressions for both 
and find at what value of t we need to evaluate our distance.
For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form 
The equation for the runner becomes simply 
, since you haven't moved until the heli is high enough.
The equation of the helicopter is 
since the heli is 30ft above ground when you start running.
Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when 
. in this time, you are at 
from the origin.
Plugging it in the distance formula you get: 
The answer would be C: 5^4
You can see the answer and solution from the picture
Answer:
A. Scalene Triangle
Step-by-step explanation:
On a Scalene Triangle all angles are different.
