Answer:
Step-by-step explanation:
The question is incomplete. The complete question is:
Based on data collected by the National Center for Health Statistics and made available to the public in the Sample Adult database (A-5). an estimate of the percentage of adults who have at some point in their life been told they have hypertension is 23.53 percent. If we select a simple random sample of 20 U.S. adults and assume that the probability that each has been told that he or she has hypertension is .24. find the probability that the number of people in the sample who have been told that hypertension will be: a) Exactly three (b) Three or more (c) Fewer than three (d) Between three and seven, inclusive
Solution:
This is a binomial probability distribution. If an adult is selected randomly, the outcome is either he has been told that he has hypertension or he has not been told. The probability of success, p would be that a randomly selected adult, x has been told. Therefore,
p = 0.24
n = 20
a)We want to determine P(x = 3). From the binomial probability distribution calculator,
P(x = 3) = 0.15
b) P(x ≥ 3) = 0.89
c) P(x < 3) = 0.11
d) P(3 ≤ x ≤ 7)
It would be P(x ≤ 7) - P(x ≥ 3)
P(x ≤ 7) = 0.92
Therefore,
P(3 ≤ x ≤ 7) = 0.92 - 0.89 = 0.03
That expression can be written as:
Hope it helped,
Happy homework/ study/ exam!
Answer:
The t-score is t = 2.457.
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 31 - 1 = 30
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 30 degrees of freedom(y-axis) and a one-tailed confidence level of . So we have T = 2.457.
The t-score is t = 2.457.
M= 1/2
to find this you plug in the points into the the formula m=y2-y1 / x2-x1
m=3-6 / -4-2
m=-3 / -6
this simplifies to m=1/2