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sveticcg [70]
3 years ago
12

Can you help me with this?

Mathematics
2 answers:
77julia77 [94]3 years ago
3 0

Answer:

the answer is a


Arturiano [62]3 years ago
3 0

let's firstly convert the mixed fractions to improper fractions, and then multiply.


\bf \stackrel{mixed}{8\frac{2}{5}}\implies \cfrac{8\cdot 5+2}{5}\implies \stackrel{improper}{\cfrac{42}{5}}~\hfill \stackrel{mixed}{5\frac{1}{2}}\implies \cfrac{5\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{11}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{42}{5}\cdot \cfrac{11}{2}\implies \cfrac{42}{2}\cdot \cfrac{11}{5}\implies 21\cdot \cfrac{11}{5}\implies \cfrac{231}{5}\implies 46\frac{1}{5}

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Please select the best answer from the choices provided
Ira Lisetskai [31]

<u>Answer:</u>

The correct answer option is c. \frac{1}{9a^2}.

<u>Step-by-step explanation:</u>

We are given an expression (27a^{-3})^{-\frac{2}{3} } and we are supposed to simplify it.

We can also write (27a^{-3})^{-\frac{2}{3} } as (\frac{3^3}{a^3} )^{-\frac{2}{3} }.

We know the power rule (a^m)^n=a^{mn} which means that to raise a power to a power you need to multiply the exponents.

So multiplying the exponents to get:

\frac{3^{(3.-\frac{2}{3})} }{a^{(3.\frac{2}{3})} }\\\\\frac{3^{-2}}{a^2}\\ \\\frac{1}{3^2a^2} \\\\\frac{1}{9a^2}

Therefore, the correct answer option is c. \frac{1}{9a^2}.

4 0
3 years ago
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Talja [164]

Answer:

45

Step-by-step explanation:

1/6 of 54= 9

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3 years ago
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ICE Princess25 [194]

Step-by-step explanation:

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3 years ago
Simplify (-5i)+(5-1)+6
Liono4ka [1.6K]

Hi there


-5i + 5-1 + 6

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That's the answer :0

I hope that's help... Do you have any question ?

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3 years ago
Is the product of two integers positive, negative, or zero?
ss7ja [257]

The product of a negative integer and a positive integer is a negative integer. The product of two positive integers or two negative integers is a positive integer. That means if you multiply two OF the same sign numbers, the product is always positive. SAME.

8 0
4 years ago
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