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Jlenok [28]
2 years ago
5

Simplify: (+8) + (-12) x (-7) - (15 - 7)​

Mathematics
2 answers:
Ray Of Light [21]2 years ago
8 0

Answer:

15-7 = 8

-12 * -7 = 84

8 +84 = 92

92-8 = 84

84

Step-by-step explanation:

Hope this helps!

Plz mark branliest

natita [175]2 years ago
4 0

Answer:

15-7 = 8

-12 * -7 = 84

8 +84 = 92

92-8 = 84

84

Give the other person brainliest :)

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The value of the given digits the 4s in 244
Digiron [165]
244

The 4's are in the ONE's and TEN's places
4 0
3 years ago
2+2+4= 8 x 12=<br> .........
Sveta_85 [38]

Answer:

96

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
At a garden shop, a customer buys 5 geraniums and 4 lilies for $48. Another customer pays $58 for 4 geraniums and 6 lilies. Writ
masha68 [24]

Answer:

A lily costs $7 and a geranium $4.

Step-by-step explanation:

From the question, we can write two equations. let the number of lilies be l and the number of geraniums be g, then:

5 g + 4 l = 48

4 g + 6 l = 58

Multiply the first equation by 4 and the second by 5, the number of lilies in the other gives:

20 g + 16 l = 192

20 g + 30 l = 290

Subtract the first equation from the second gives:

14 l = 98  which dividing by 14 gives  l = 7

Substituting the value  l = 7  in the first equation gives:

5 g + 28 = 48

Subtract 20 from both sides gives:

5 g = 20  divide by 5 gives  g = 4

So, a lily costs $7 and a geranium costs $4.

7 0
3 years ago
PLZ HEEEELP!!!!! 10 POINTS!!!!
katrin2010 [14]

Answer:

Step-by-step explanation:

Part a

We need two inequalities, one for time worked at each job and the other

for amounts of money earned.

time:  Let b and c represent the time (number of hours) worked at babysitting and landscaping respectively.  Then b + c ≤ 20 hrs/wk

earnings:  Let ($3/hr)(b) represents the amount of money earned babysitting for b hour.  Let  ($7/hr)(c) represent the money earned working at landscaping.  These amounts are <em>per week</em>.  The appropriate inequality is  ($3/hr)(b) +  ($7/hr)(c) ≥ $84 per week.  The other inequality is

b + c ≤ 20 hrs/wk.

Part b:

As before, b + c ≤ 20 hrs/wk.  What happens if Chet spends all his 20 hours babysitting?  To answer this, set c = 0 (no landscaping hours).  Then b ≤ 20 hours.  At $3/hr, he could earn only $60 and have no time left for landscaping.  Not good.

Let's experiment:  suppose he works 15 hours babysitting and 5 hours landscaping.  His earnings would be $45 + $35, or $80.  Still not enough; he wants to earn $84 total.    Let's redistribute his time and try again:  suppose he works 14 hours babysitting and 6 hours landscaping; his earnings would be $42 + $42, or $84.  So {b = 14 hours and c + 6 hours} is a solution.  As we continue to reduce the number of hours Chet works babysitting and correspondingly increase those he works landscaping, his earnings will go up, beyond $84.

Here's a table that summarizes this:

babysitting          landscaping    total amount

  hours                   hours               earned

      15                          5                      $60 (not acceptable)

       14                         6                       $84 (borderline acceptable)

       12                          8                       $36 + $42 = $78 (great)

        6                          14                       $116 (greater still)

         2                          18                     $132

          1                           19                      $134

          0                          20                      $140

Summary:  Chet can work anywhere from 0 to 14 hours babysitting and expect to earn $84 or more.

4 0
3 years ago
A group of tourists can be sorted into tour boats in groups of 4 or in groups of 6. In either case, there are no empty seats. Fi
Jobisdone [24]

Answer: there are 36 tourists.

Step-by-step explanation:

Ok, we have two integer numbers:

T, the number of tourists and S, the number of seats.

Such that, if we divide the tourists into groups of 4 and in groups of 6, we end with no empty seats.

Knowing that the number S must be an integer, and when we divide T into groups of 4 and 6 we end with no empty seats, this means that T can be divided by 4 and by 6.

This means that T is a common multiple of 4 and 6

Now, we also know that 25 < T < 45.

Then let's see which ones are the multiples of 4 between 25 and 45.

4*7 = 28

4*8 = 32

4*9 = 36

4*10 = 40

4*11 = 44.

Now, the multiples of 6 in that range are:

6*5 = 30

6*6 = 36

6*7 = 42.

You can see that 36 is a common multiple, other way to see it is:

4*9 = (2*2)*(3*3) = 2*2*3*3 = (2*3)*(2*3) = 6*6

So the numer of tourist must be 36.

8 0
3 years ago
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