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Amiraneli [1.4K]
3 years ago
13

If f(x)=-5squared -4 and g(x) = -3x-2find (f+g)(x)

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0

Answer:

-3x + 19

Step-by-step explanation:

f(x) = -5² - 4

f(x) = 25 - 4

f(x) = 21

(f+g)(x) = f(x) + g(x)

21 + -3x - 2

-3x + 19

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Match the correct equation for the variable n with * for number of times compound interest is figured. quarterly d.___ semi-annu
Dvinal [7]

Answer:

quarterly N = 4

semi-annually N = 2

Monthly N = 12

annually N = 1

Step-by-step explanation:

Given the following compound interest times :

N = number of times interest is compounded per period :

A period is regarded as a whole year.

Interest compounded;

QUARTERLY = Every 4 months per period = 12/3= 4

SEMI ANNUALLY = Every 6 months per period = 12/6 = 2

MONTHLY = Every month = 12 / 1 = 12

ANNUALLY = Every 12 months = 12 /12 = 1

3 0
2 years ago
Find the vertex of the graph of f(x)=-4(x-1)(x+5)
madreJ [45]

The vertex of the graph is (h, k) = (- 2, 36).

<h3>How to find analytically the vertex of a quadratic equation</h3>

In this question we have a quadratic equation of the form f(x) = a · (x - r₁) · (x - r₂) and we need to transform the expression into its vertex form of determine the coordinates of the vertex. First, we need to exprand the expression:

f(x) = - 4  · (x - 1) · (x + 5)

f(x) = - 4 · (x² + 4 · x - 5)

f(x) = - 4 · x² - 16 · x + 20

Now we proceed to complete the square:

f(x) = - (4 · x² + 16 · x - 20)

- f(x) = 4 · x² + 16 · x - 20

- f(x) = (2 · x)² + 8 · (2 · x) - 20

- f(x) + 36 = (2 · x)² + 8 · (2 · x) + 16

- f(x) + 36 = (2 · x + 4)²

- f(x) + 36 = 4 · (x + 2)²

f(x) - 36 = - 4 · (x + 2)²

The vertex of the graph is (h, k) = (- 2, 36).

To learn more on quadratic equations: brainly.com/question/17177510

#SPJ1

7 0
1 year ago
I really don’t know how to do this and i could really use some help :) please
Firlakuza [10]

Answer:oh goodness

Step-by-step explanation:

3 0
3 years ago
Pls do it fast ill mark you brainliest
anygoal [31]

Answer:

\sf  y=7\frac{2}{3} and \sf x = \frac{2}{3}

Explanation:

\sf (1)  \  \  (2x+y = 9)

\sf (1) \ \  (2x+5y = 37)

<u>solve for y</u>:

\sf 2x + y = 9

\sf 2x + 5y = 37

-----------------

\sf 0x + 6y = 46

\sf 6y = 46

\sf  y=\frac{23}{3}

\sf  y=7\frac{2}{3}

<u>solve for x</u>:

\sf 2x + y = 9

\sf 2x = 9 - y

\sf 2x = 9 - \frac{23}{3}

\sf 2x = \frac{4}{3}

\sf x = \frac{2}{3}

8 0
2 years ago
Help asap please!! &lt;3
Sergio039 [100]

Answer:

9.3%

Step-by-step explanation:

You are welcome!!

3 0
3 years ago
Read 2 more answers
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