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Arada [10]
3 years ago
10

At lunch 3 1/4 small pizzas were equally divided amping students. If each student ate 1/4 of a pizza, how many students were fed

?
Mathematics
1 answer:
Vilka [71]3 years ago
5 0

Answer:

13 students were fed

Step-by-step explanation:

now first in order to count we will have to turn 3 1/4 into a whole number which means we will have to multiply the denomintor by 3 and add it to the numerator which is 1

4 x 3= 12 ..... 12 + 1 = 13  

13/4  and the denominator always stays the same

and now to count we will have to divide 13/4 divided by 1/4

now instead of dividing you can just multiply them by switching the denominator and numerator  1/4  to  4/1  

13/4 x 4/1

52/4

13


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Point B is located between points A and C, AB= X^2-10, BC= 2X +2 and AC= 16 ,solve for X
Irina18 [472]
Drawing a picture would be helpful.
So you have AB and BC, and AC is ALL of AB and BC. In other words, 
AC = AB+BC.
Now plug in what the problem gave you.
(16) = (x^2 -10) + (2x + 2)
16 = x^2 + 2x - 8
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0 = (x+6)(x-4)
x = -6, 4
7 0
3 years ago
Math question screenshot down below
lara31 [8.8K]
(4+3)x6
Or
6x4 + 6x3
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3 0
3 years ago
The perimeter of an equilateral triangle is at most 45 centimeters Find the possible length of each side
Tju [1.3M]

The perimeter is  3  times the length of each side:

p = 3s


If the perimeter is at most  45 cm, then

p ≤ 45 cm

3s ≤ 45 cm

           45 cm
s  ≤  —————
               3


s ≤ 15 cm


So each side is at most  15 cm.


I hope this helps. =)

3 0
3 years ago
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nasty-shy [4]
This question relates to scale factor
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Two sides are given, so you can find the scale factor.
20/6=10/3=3.3333333
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6 0
2 years ago
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sam
Scorpion4ik [409]

Answer:

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of students who take notes

\hat p represent the estimated proportion of students who take notes

n is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

6 0
3 years ago
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