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kati45 [8]
2 years ago
12

30/90 del número de plantas en un cultivo de caña está contaminada. De estas, el 1/2 ha sido tratada. ¿Cual es la fracción del n

úmero de plantas del cultivo que no ha sido tratada?
Mathematics
1 answer:
Helen [10]2 years ago
5 0

Answer:

1/6

Step-by-step explanation:

De la pregunta, sabemos:

30/90 del número de plantas de un cultivo de caña está contaminado.

30/90, simplificamos aún más

30/90 => 3/9 => 1/3

De estos, la mitad han sido tratados.

La fracción de los cultivos tratados son:

1/2 de 3/9 = 1/2 × 1/3

= 1/6

La fracción del número de plantas del cultivo que no ha sido tratada se calcula como:

1/3 - 1/6

El mínimo común denominador es 6

= (2 × 1) - (1 × 1) / 6

= 2 - 1/6

= 1/6

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-3/5x - 7/20x + 1/4x= -56
romanna [79]

Answer:

x = 80

Step-by-step explanation:

Combine − 3/5x and 7/20x to get -19/20x.

Then combine -19/20x and 1/4x and you get -7/10x.

Then you multiply both sides by -10/7 which is the reciprocal of -7/10.

Make -56(-10) one fraction.

Multiply -56 and -10 and you get 560.

Then divide 560 by 7 to get 80.

 

​  

8 0
3 years ago
Read 2 more answers
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k0ka [10]

Step-by-step explanation:

if b+c=0

b=-c

x^b=x^-c

so

1/[2(x^b)+1]

6 0
2 years ago
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Kisachek [45]
1) 4/2 2) 1/3 3) 3/-1
4 0
3 years ago
How do I solve this problem?
Andrews [41]

so the line is dog so we know the full line is 60 units long. The 2 parts (do and og) add up to the full length so we can make the equation:

(4x-3)+(2x+21)=60

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3 years ago
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stich3 [128]

Answer:

35 quizzes

Step-by-step explanation:

We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.

We do this by using the formula \displaystyle nCr=\frac{n!}{r!(n-r)!} which describes the number of ways we can choose r objects given n possible choices. So, if n=7 and r=4, then:

_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35

Hence, the teacher can make 35 different geometry quizzes.

3 0
2 years ago
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