Hello,
Let's suppose f(x)=3x+7
f(a-1)=3(a-1)+7=3a-3+7=3x+4
Answer B with a sign "++++++++++++++++++++++++++++"
Answer:
12 is the answer
Step-by-step explanation:
Answer:
1) n^2 – 3 n + 8 4^2 – 3*4 + 8 = 12
2) (x^2 – 4 y) / 2 (16 + 12) / 2 = 14
3) 4 * |-7 – 2| = 4 * 9 = 36 Abs -9 = 9
4) 19 – x^2 = 19 – 25 = -6 (-5)^2 = 25
5) S^2 t – 10 = -8^2 * ¾ -10 = 64 * ¾ - 10 = 38
6) 4 p^2 + 7 q^3 = 4 * 9 + 7 * (-8) = - 20 (-2)^3 = -8
Answer:
Step-by-step explanation:
It appears you're trying to simplify ...
The final factor cancels the denominator of the fraction, so we have ...
_____
The applicable rules of exponents are ...
(ab)^c = (a^c)(b^c)
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
Answer:
P(AUB)'=2/15
Step-by-step explanation:
According to the Question,
- Given That, A and B be two independent events. If P(A)=3/5 and P(B')=1/3.
So, P(B)=1-P(B') ⇒ P(B)=1-(1/3) ⇔ P(B)=2/3
- The Product Rule of Probability says For independent events P(A∩B)=P(A)×P(B)
P(A∩B)=3/5 × 2/3 ⇒ P(A∩B)=2/5
- We know, P(AUB)=P(A)+P(B)-P(A∩B)
Thus, P(AUB)= 3/5 + 2/3 - 2/5
P(AUB)=1/5 + 2/3
P(AUB)=(3+10)/15 ⇔P(AUB)=13/15
- Now, The Value Of P(AUB)'=1-P(AUB) ⇔ 1 - 13/15 ⇒ P(AUB)'=2/15
