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maxonik [38]
3 years ago
8

Rewrite V=lwh to isolate the variable w then the literal equation becomes w=v/lh true or false

Mathematics
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

True

Step-by-step explanation:

V=lwh\\\\lwh=V\\\\\frac{lwh}{lh}=\frac{V}{lh}\\\\  \boxed{w=\frac{V}{lh}};  l\neq  0

The answer should be true.

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QR bisects angle PQS. Angle PQR= (4×-10) degrees and Angle QRS =(-3x+130)degrees.
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How do you explain if something IS NOT a perfect square/ square number?
mariarad [96]

Answer:

A square number cannot be a perfect number. 0, 1, 5, 14, 30, 55, 91, 140, 204, 285, 385, 506, 650, 819, 1015, 1240, 1496, 1785, 2109, 2470, 2870, 3311, 3795, 4324, 4900, 5525, 6201... The sum of the first odd integers, beginning with one, is a perfect square: 1, 1 + 3, 1 + 3 + 5, 1 + 3 + 5 + 7, etc.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the bas
neonofarm [45]

Answer:  The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

Step-by-step explanation:

I will assume that the exercise says "\frac{1}{3} times the base and height of Jerry’s rhombus".

The area of a rhombus can be calculated with the following formula:

A=b*a

Where "b" is the length of the base  and "a" is the altitude or the height.

Then, you can calculate the area using the formula shown above.

Therefore, you get:

1. Jerry's rhombus:

A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2

2. Charlene's rhombus:

A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2

Dividing the area calculated, you get:

\frac{135\ in^2}{15\ in^2}=9

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

7 0
4 years ago
Read 2 more answers
Answers anyone will give thanks and brainliest answer
weeeeeb [17]
3. A 4.B 5.B Very happy to help you!
5 0
3 years ago
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givi [52]
Bare with me a minute, I am still trying to figure it out. Here is what I have so far.

6 0
3 years ago
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