Answer:
11
Explanation:
Moles of KOH =
Volume of water = 10 liters
Concentration of KOH is given by
is strong base so we have the following relation
So, pH of the solution is 11
Answer:
See explanation
Explanation:
In electrophillic aromatic substitution, an electrophile attacks the aromatic ring and resonance structures are created.
We know that the nature of the substituents already present in the ring determines the position to which the incoming substituent is directed.
-OCH3 is an ortho-para director. If the -OCH3 is present at position 1 and the ring is brominated at position 4, the resonance structures shown in the image attached are observed.
Answer:
Solution A has the higher percent ionization and the higher pH.
Explanation:
Percent ionization depends on the concentration of acid in a solution. If the solution having more concentration of acid so the percent ionization will be lower while if the solution have low amount of acid i. e. dilute solution so the percent ionization will be higher. In solution A, the concentration of HNO2 is lower which is an acid so the percent ionization is higher and the pH of the solution is also higher as compared to solution B.
A) a symbol showing that it is poisonous
b) gloves and other bodily protection
c) a symbol showing that it is flammable
d) they most likely were unaware. I do not think they would intentionally hurt people.