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Gennadij [26K]
3 years ago
6

How to set an experiment in which I need to find volume of one water drop?

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
4 0
Microscale could be best bet as evaboration and other factors can come in play. otherwise contact angle measurements could have something related calculated via surface tension.

something that is possible, calculating mols via gravimetry.
finding the suitable material could be tricky as if it needs to be instant. silica gel doesn't necessarily work

adsorption vs. absorption
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The atomic mass and abundance of Cr-50 is 49.946 amu and 4.3%. The atomic mass and abundance of Cr-52 is 51.941 amu and 83.8%. T
Sati [7]
Multiply the mass by the abundance and add each. Make sure to convert the percentage into a decimal. (49.946 * .043) + (51.941 * .838) + (52.941 * .095) + (53.939 * .024) = 51.99 round up using sig figs and the answer is c. 52.00 amu
6 0
3 years ago
If 38.5 grams of potassium react with excess oxygen gas, how many grams of potassium oxide can be produced? 4K + O2 yields 2K2O
Lera25 [3.4K]

Answer:

46.40 g.

Explanation:

  • It is a stichiometric problem.
  • The balanced equation of the reaction: 4K + O₂ → 2K₂O.
  • It is clear that 4.0 moles of K reacts with 1.0 mole of oxygen produces 2.0 moles of K₂O.
  • We should convert the mass of K (38.5 g) into moles using the relation:

<em>n = mass / molar mass,</em>

n = (38.5 g) / (39.098 g/mol) = 0.985 mole.

<em>Using cross multiplication:</em>

4.0 moles of K produces → 2.0 moles of K₂O, from the stichiometry.

0.985 mole of K produces → ??? moles of K₂O.

∴ The number of moles of K₂O produced = (0.985 mole) (2.0 mole) / (4.0 mole) = 0.4925 mole ≅ 0.5 mole.

  • Now, we can get the mass of K₂O:

∴ mass = n x molar mass = (0.5 mole) (94.2 g/mol) = 46.40 g.

6 0
3 years ago
PLEASE HELP!!
NARA [144]
We can skip option B and D because NaCl is salt and H₂SO₄ is a strong acid.
Neutralization reactions are those reactions in which acid and base react to form salt and water.
As water being amphoteric in nature can react with HCl as follow,

                           HCl  +  H₂O   ⇆  H₃O⁺  +  OH⁻

In this case no salt is formed, so we can skip this option.

Ammonia being a weak base can abstract proton from HCl as follow,

                              HCl  +  NH₃  →  NH₄Cl

Ammonium Chloride is a salt. So, among all four options, Option-C is the correct answer.
3 0
3 years ago
Read 2 more answers
How many atoms are in 294 g of copper?
mote1985 [20]

Answer

2.1 x 10 ^23

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7 0
3 years ago
A HOMOGENEOUS LIQUID THAT CANNOT BE SEPARATED INTO ITS COMPONENTS BY DISTILLATION BUT CAN BE DECOMPOSED BY ELECTROLYSIS IS CLASS
nata0808 [166]

Answer:

ELEMENTS

Explanation:

CUZ AN A

ELEMENT IS A GROUP OF ATOMS THAT CANNOT BE BROKEN DOWN BY ANY CHEMICAL OR PHYSICAL MEAN

7 0
3 years ago
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