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Alika [10]
2 years ago
8

2055 Q. No. 10^-2

Chemistry
1 answer:
insens350 [35]2 years ago
5 0

Answer:

11

Explanation:

Moles of KOH = 10^{-2}

Volume of water = 10 liters

Concentration of KOH is given by

[KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}

[KOH] is strong base so we have the following relation

[KOH]=[OH^{-}]=10^{-3}\ \text{M}

pOH=-\log [OH^{-}]=-\log10^{-3}

\Rightarrow pH=14-3=11

So, pH of the solution is 11

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The original results have not been replicated consistently and reliably.

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3 years ago
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what mass of carbon dioxide gas would be produced if 10g of calcium carbonate reacted with an excess of hydrochloric acid?
LuckyWell [14K]
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</span>Chemical reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.
m(CaCO₃) = 10 g.
n(CaCO₃) = 10 g ÷ 100 g/mol.
n(CaCO₃) = 0,1 mol.
From chemical reaction: n(CaCO₃) : n(CO₂) = 1 : 1.
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7 0
3 years ago
How many pounds of manganese are in 1.261 tons of Mn2O3?
Alina [70]

Answer:

2000pound

Explanation:

Manganese metal is produced from the manganese(III) oxide, Mn2O3, which is found in manganite, a manganese ore. The manganese is reduced from its +3 oxidation state in Mn2O3 to the zero oxidation state of the uncharged metal by reacting the Mn2O3 with a reducing agent such as aluminum or carbon. How many pounds of manganese are in 1.261 tons of Mn2O3? (1 ton = 2000 pounds)

About 40 different substances called organophosphorus compounds are registered in the United States as insecticides. They are considered less damaging to the environment than some other insecticides because they breakdown relatively rapidly in the environment. The first of these organophosphorus insecticides to be produced was tetraethyl pyrophosphate, TEPP, which is 33.11% carbon, 6.95% hydrogen, 38.59% oxygen, and 21.35% phosphorus. It has a molecular mass of 290.190.

4 0
2 years ago
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope
qaws [65]

Answer:

<u><em>I HOPE IT WILL BE YOUR ANSWER:</em></u>

Explanation:

As given

60 min = 50 gm        (1)

then we know half-life mean half amount decay time

so we can write as the half of 200 is 100 gm hence

T 1/2 = 100               (2)

solving these two equation by cross multiplication we will get

T 1/2 = 120 min

<em><u>THANKS FOR ASKING QUESTION</u></em>

6 0
3 years ago
A cylindrical tube 13.5 cm high and 4.5 cm in diameter is used to collect blood samples. How many cubic decimeters (dm3) of bloo
Aleks [24]

Answer:

The cylindrical tube can hold 0.215 cubic decimeters of blood.

Explanation:

Diameter of the cylindrical tube = d = 4.5 cm

r = d/2 ,r = 2.25 cm

Height of the cylindrical tube = h = 13.5 cm

Volume of the cylinder = V = \pi r^2h

V=3.14\times (2.25 cm)^2\times 13.5 cm

V=214.6 cm^3=0.2146 dm^3\approx 0.215 dm^3

1 cm^3=0.001 dm^3

The cylindrical tube can hold 0.215 cubic decimeters of blood.

3 0
3 years ago
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