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Alika [10]
2 years ago
8

2055 Q. No. 10^-2

Chemistry
1 answer:
insens350 [35]2 years ago
5 0

Answer:

11

Explanation:

Moles of KOH = 10^{-2}

Volume of water = 10 liters

Concentration of KOH is given by

[KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}

[KOH] is strong base so we have the following relation

[KOH]=[OH^{-}]=10^{-3}\ \text{M}

pOH=-\log [OH^{-}]=-\log10^{-3}

\Rightarrow pH=14-3=11

So, pH of the solution is 11

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3 years ago
A sample of glucose contains 1.250x10^21 carbon atoms, how many atoms of hydrogen does it contain?
dybincka [34]

Answer:

Hydrogen = 2.5 * 10^21

Explanation:

Chemical Formula Glucose: C₆H₁₂O₆

One of the ways you could do  this is to notice that for every carbon atom there are two Hydrogen atoms. You can state this more formally by using the formula to set up a ratio: 12/6 = hydrogen to Carbon

So if there are 1.250 * 10^21 Carbon atoms in the Glucose sample, then there will be twice as many hydrogen atoms.

H = 2 * 1.25 * 10^21 = 2.5 * 10^21 atoms

You could do this more formally by setting up a proportion.

6 Carbon / 12 Hydrogen = 1.25*10^21 /  x         Cross Multiply

6*x = 12 * 1.25*10^21                                           Combine the right

6x = 1.5 * 10^22                                                  Divide by 6

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5 0
2 years ago
Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas
Gwar [14]

The equation structure for the above mentioned reaction can be written as  

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<u>Explanation:</u>

Considering the above reaction, When Boron sulfide, reacts with water more violently to form boric acid and hydrogen sulfide gas.

B_{2} S_{3}+H_{2} O \rightarrow H_{3} B O_{3}+H_{2} S \uparrow

In order to balance the equation, we can do as follows.There are 2 B - atoms on both sides of the equation, but only 2 H - atoms, and one O - atom on LHS, so we have to balance it by putting 6 in front of water and 2 in front of Boric acid and 3 in front of hydrogen sulphide gas, so that we have 2 B - atoms, 3 - S atoms, 12 H - atoms on both sides of the equation, and it is balanced. Balanced equation is given as,

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

Thus a Balanced equation of the above mentioned reaction is written.

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3 years ago
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Whitepunk [10]

Hey there!

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Next, balance H.

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Lastly, balance Na.

One on the left, two on the right. Add a coefficient of 2 in front of Na.

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This is our final balanced equation.

Hope this helps!

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Answer:

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