Molar mass KCl = <span>74.5513 g/mol
Number of moles:
21.9 / 74.5513 => 0.293 moles
Volume = 869 mL / 1000 => 0.869 L
Molarity = moles / Volume
Molarity = 0.293 / 0.869
=> 0.337 M</span>
I believe the answer to this question is b
Answer:
Percent mass of KNO3 in solution = 11% (Approx)
Explanation:
Given:
Mass of KNO3 = 25 grams
Mass of H2O = 200 grams
Find:
Percent mass of KNO3 in solution
Computation:
Mass of solution = 25 + 200 = 225 grams
Percent mass of KNO3 in solution = [25/225]100
Percent mass of KNO3 in solution = 11.111%
Percent mass of KNO3 in solution = 11% (Approx)
Answer:
Explanation:
The relation between new scale and absolute temperature scale is given as follows
Aw = 2 K
for K = 273.15 ( freezing point of water at absolute scale )
Aw = 2 x 273.15 = 546.3 K
So each division of new scale is half the each division of absolute scale
each division of new scale is small .
The value of R = 8.314 J per mole per K
Here per K is equivalent to 2Aw
So the vale of R in new scale = 8.314/2 J per mole per Aw
= 4.157 J per mole per Aw
k = R / N
= 4.157 / 6.02 x 10²³
= .69 x 10⁻²³
= 6.9 x 10⁻²⁴ J per molecule per Aw .
He thought it looked like plum pudding, with positively charged balls(pudding) and negatively charged raisins