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Marta_Voda [28]
3 years ago
9

If a mixture of a given percentage or ratio strength is diluted to twice its original quantity, its active ingredient will be co

ntained in twice as many parts of the whole, and its strength, therefore, will be?
​
Chemistry
1 answer:
OlgaM077 [116]3 years ago
8 0

Answer:

if a mixture of a given percentage or ratio strength is diluted to twice its original quantity, its active ingredient will be contained in twice as many parts of the whole, and its strength therefore will be reduced by one-half

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What is the mass of 20.0 L of sulfur dioxide (SO2) at STP?
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Answer:

Mass = 57.05 g

Explanation:

Given data:

Volume of SO₂ = 20.0 L

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The given problem will be solve by using general gas equation,

PV = nRT

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It was calculated that 4.3mL of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M Mg(OH)2. Show evidence 2 HCl(aq) + Mg(OH)2
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Answer:

See explanation.

Explanation:

Hello,

In this case, for the described chemical reaction:

2 HCl(aq) + Mg(OH)2(aq) → MgCl2(aq) + 2 H2O(l)

We can notice there is a 2:1 molar ratio between the moles of hydrochloric acid and magnesium hydroxide, therefore, at the equivalence point:

n_{HCl}=2*n_{Mg(OH)_2}

And in terms of volumes and concentrations we verify:

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So we use the given data to proof it:

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