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Marta_Voda [28]
3 years ago
9

If a mixture of a given percentage or ratio strength is diluted to twice its original quantity, its active ingredient will be co

ntained in twice as many parts of the whole, and its strength, therefore, will be?
​
Chemistry
1 answer:
OlgaM077 [116]3 years ago
8 0

Answer:

if a mixture of a given percentage or ratio strength is diluted to twice its original quantity, its active ingredient will be contained in twice as many parts of the whole, and its strength therefore will be reduced by one-half

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3 years ago
Calculate the solubility of carbon dioxide at 400 kPa.
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The solubility of carbon dioxide at 400 kPa  at room temperature is ;

( B ) 0.61 CO2/L

<u>Given data </u>

pressure of CO₂ = 400 Kpa = 3.95 atm

Kh of CO₂ = 3.3 * 10⁻² mol/L.atm

<h3>Calculate the solubility of carbon dioxide </h3>

Solubility = pressure * Kh value of CO₂

                = 3.95 atm * 3.3 * 10⁻² mol / L.atm

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Hence we can conclude that the solubility of CO₂ at 400 kPa is 0.13 mol/l  CO₂.

Learn more about solubility : brainly.com/question/23946616

From the options the closest answer is ( B ) 0.61 CO₂ / L

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