If a mixture of a given percentage or ratio strength is diluted to twice its original quantity, its active ingredient will be co
1 answer:
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Answer: 0.30 M
Explanation:
According to the neutralization law,
where,
= molarity of
solution = ?
= volume of
solution = 24.6 ml
= molarity of
solution = 0.222 M
= volume of
solution = 33.0 ml
= valency of
= 21
= valency of
= 1
Therefore, the molarity of the HCI solution is 0.30 M