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3 years ago

15

Using the Quotient of Powers Property Simplify 12x^9/2x^3 6x^2 6x^6 10x^3 10x^6

1 answer:

AysviL [449]3 years ago

3 0

Answer:

It is 6x^6 ... since you divide 12÷2=6 and you subtract exponents

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Figure out this missing number pattern:\<br> 1,1,2,3,5_,_,_

Mamont248 [21]

What you have here is the fibonacci sequence.
Each number in the sequence adds itself to the number before it.
1+1 = 2
1+2 = 3
3+2 = 5
5+3 = 8
8+5 = 13
the sequence is 0,1,1,2,3,5,8,13

8 0

2 years ago

What is the best answer to solution of x^2 + 16 = 0?

kolezko [41]

Answer:

4. C. x = 4 or -4

Step-by-step explanation:

since both terms are perfect squares, factor using the difference of squares formula, a² - b² = ( a + b ) ( $\alpha$ - b ) where

5 0

3 years ago

Solve 93 divide by 4 using the area model, long division, and the Distributive property.

stepan [7]

Answer:

oh wow let me garba cac

Step-by-step explanation:

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3 years ago

Read 2 more answers

He buys a jewel for $180, then sells it for $216. Find his percentage profit.

yan [13]

Answer:20%

Step-by-step explanation:216-180=36. 36/180=.20

6 0

2 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago