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Oliga [24]
3 years ago
15

Using the Quotient of Powers Property Simplify 12x^9/2x^3 6x^2 6x^6 10x^3 10x^6

Mathematics
1 answer:
AysviL [449]3 years ago
3 0

Answer:

It is 6x^6 ... since you divide 12÷2=6 and you subtract exponents

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Figure out this missing number pattern:\<br> 1,1,2,3,5_,_,_
Mamont248 [21]
What you have here is the fibonacci sequence. 
Each number in the sequence adds itself to the number before it.
1+1 = 2
1+2 = 3
3+2 = 5
5+3 = 8
8+5 = 13
the sequence is 0,1,1,2,3,5,8,13
8 0
2 years ago
What is the best answer to solution of x^2 + 16 = 0?​
kolezko [41]

Answer:

4. C. x = 4 or -4

Step-by-step explanation:

since both terms are perfect squares, factor using the difference of squares formula, a² - b² = ( a + b )  ( \alpha - b ) where

5 0
3 years ago
Solve 93 divide by 4 using the area model, long division, and the Distributive property.
stepan [7]

Answer:

oh wow let  me garba cac

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
He buys a jewel for $180, then sells it for $216. Find his percentage profit.
yan [13]

Answer:20%

Step-by-step explanation:216-180=36. 36/180=.20

6 0
2 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
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