Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
x = [-5 ± √(25 - (104) ) ] / ( -4 )
x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
The ratio is 1:5 tbh or that’s what I think ahahahah
First term = T(1) is obtained by plugging n = 1 into the formula,
thus First term = 1^2 - 4 = 1 - 4
= 3 (answer)
Answer:
17
Step-by-step explanation:
Properties used:-
All sides of rhombus are equal therefore in the triangles
EQUAL SIDE OPPOSITE TO ANGLES, ANGLES BECOME EQUAL
then we use alternate interior angles
Then we get,
3x-11=x+23
2x=34
x=17
