Question

Boron (B): 1sE2sF2pG

Answer 1

1s2 2s2 2p1
so E & F =2
G =1

Answer 2

Answer: For the given electronic configuration, E will be 2, F will be 2 and G will be 1.

Explanation:

Boron is the 5th element of the periodic table. The number of electrons present in this element will be equal to the atomic number which is 5.

Electronic configuration of an element is the denoted as the total number of electrons present in that element.

First 2 electrons will be filled in 1s orbital. Then two electrons will be filled in 2s-orbital and rest in 2p-orbital.

Hence, the electronic configuration of Boron becomes: $1s^22s^22p^1$

Therefore, E will be 2, F will be 2 and G will be 1.