IT will be Refraction of light
False
explanation
All of the elements with atomic numbers 1 to 92 can be found in nature, have stable or very long half-life isotopes, and are created as common products of the decay of uranium and thorium.
Volume of tank =
(given)
Since,
So,
![1 m^{3} = 35.287 ft^{3}](https://tex.z-dn.net/?f=1%20m%5E%7B3%7D%20%3D%2035.287%20ft%5E%7B3%7D)
For
:
![6.9\times 35.287 ft^{3} = 243.4803 ft^{3}](https://tex.z-dn.net/?f=6.9%5Ctimes%2035.287%20ft%5E%7B3%7D%20%3D%20243.4803%20ft%5E%7B3%7D)
The significant rule for multiplication, states that the number of significant figures in the answer obtained by multiplication is determined by the value with the lowest number of significant digits.
Since, the minimum number of decimal places in the above multiplication operation is 1 so, the final result must be upto 1 decimal place only.
![243.4803 ft^{3} \simeq 243.5 ft^{3}](https://tex.z-dn.net/?f=243.4803%20ft%5E%7B3%7D%20%5Csimeq%20243.5%20ft%5E%7B3%7D)
Hence, volume in
is 243.5.
It allows a scientist to understand the history of metamorphic rock by estimating the temperature, depth, and pressure at which a rock undergoes metamorphism.
Hope that helped!
When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute:
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025= 0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
= 0.0075 * 63.546 =0.477 g