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Lostsunrise [7]
4 years ago
9

Elements may be individual atoms or they may form molecules. Compounds can only have which form? PLEASE ANSWER FAST WILL GIVE BR

AINLIEST FIRST ANSWER
Chemistry
2 answers:
son4ous [18]4 years ago
7 0

Answer:

All compounds are molecules

I got you! i hope i helped

Explanation:

oksian1 [2.3K]4 years ago
6 0

Answer : The compounds can only have molecule form.

Explanation :

Pure substance : It is defined as a substance that is made by the combination of only one type of atom or only one type of molecule.

Compound : It is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.

Element : It is a pure substance which is composed of atoms of similar elements.

Molecule : It is the smallest particle in the chemical compound or chemical element that has the same chemical properties of that compound or element.

As per question:

  • An elements may be individual atoms or they may form molecules.

For example:

Mn is an element.

O_3 is molecule of element.

  • Compounds can only have molecule form.

For example:

KOH is molecule of compound.

H_2S is molecule of compound.

Hence, the compounds can only have molecule form.

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1) Atomic number of magnesium (Mg) is 12, it means that it has 12 protons and 12 electrons.

Electron configuration of magnesium atom: ₁₂Mg 1s² 2s² 2p⁶ 3s².

2) Atomic number of aluminium (Al) is 13, it means that it has 13 protons and 13 electrons., but if it lost one electron, it will have 12 electrons and 13 protons and become aluminium cation Al⁺.

Electron configuration of aluminium cation: ₁₃Al⁺ 1s² 2s² 2p⁶ 3s².

3) Atomic number of silicon (Si) is 14, it means that it has 14 protons and 14 electrons., but if it lost two electrons, it will have 12 electrons and 14 protons and become silicon cation Si²⁺.

Electron configuration of silicon cation: ₁₄Si²⁺ 1s² 2s² 2p⁶ 3s².


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A box experiences a force of 2 N to the left and 3 N to the right. Which is true of the box's motion?
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The box is expected to go to the right since the 3N is stronger than the 2N and the rightward force will over come the leftward force.
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How many electrons will be in the valence of non- H atoms when they make covalent bonds?
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Consider 2.4 moles of a gas contained in a 4.0 L bulb at a constant temperature of 32°C. This bulb is connected to an evacuated
Luden [163]

Complete Question

The complete question is shown on the first uploaded image

Answer

a

As the valve is opened , the gas will flow into the empty container until the both containers have the same pressure

b

\Delta H = 0\ , \Delta E = 0 , q= 0 , w= 0

c

The driving force for this process is the increase in entropy this is because the movement of the internal energy of the gas into a larger volume, what this does is that it increases the amount of disorder(entropy).

Explanation

In order to obtain the parameter in the part B of the question we are first obtain the initial pressure, using the ideal gas equation  

                      P = \frac{nRT}{V}

                     P = \frac{(2.4mol)(0.0821\frac{1 atm}{K \cdot \ mol} )}{4.0L}

                         P =15 \ atm

The next thing is to obtain the new pressure of the gas , using boyle's law

              P_1V_1 = P_2V_2

                  P_2 = \frac{P_1 V_1}{V_2}

                  P_2 = \frac{(15 \ atm)(4.0L)}{24.0 L}

                  P_2 = 2.5 \ atm    

Since the this process is isothermal , the change in heat is equal to zero

                      i.e  q = 0 J

  The workdone to move  the gas to the other container is zero because the  the pressure at this second container is zero due to the fact that it is a vacuum

    i.e  w = -P_{external} \Delta V

              =-(0 \ atm) (24.0 - 4.0L)

              = 0L \cdot atm

  Since the change in heat is zero and the workdone is zero then the change in internal energy is equal to 0

     This is because the change in internal energy is equal to a summation of change in heat and the workdone

                i.e \Delta E = q + w

                            = 0J

Generally the change in enthalpy is mathematically represented as

                \Delta H = n C_p \Delta T

Since the temperature is zero this means that the change in temperature is zero , substituting this value for change in temperature into the equation for  change in enthalpy

           \Delta H = n C_p (0)

                   = 0J

 

7 0
4 years ago
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