Answer:
a) ω1 = 18rpm ω2 = -18rpm
b) ω1 = 102rpm ω2 = 138rpm
c) ω1 = ω2 = 3.18rpm
Explanation:
For the first case, we know that each wheel will spin in a different direction but with the same magnitude, so:
ωr = 6rpm This is the angular velocity of the robot
where D is 30cm and rwheel is 5cm
One velocity will be positive and the other will be negative:
ω1 = 18rpm ω2 = -18rpm
For part b, the formula is the same but distances change. Rcircle=100cm:


Replacing values, we get:


For part c, both wheels must have the same velocity:


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Answer:
Now e is due to the ring at a
So
We say
1/4πEo(ea/ a²+a²)^3/2
= 1/4πEo ea/2√2a³
So here E is faced towards the ring
Next is E due to a point at the centre
So
E² = 1/4πEo ( e/a²)
Finally we get the total
Et= E²-E
= e/4πEo(2√2-1/2√2)
So the direction here is away from the ring
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