Question

If you have five capacitors with capacitances 0.6×10-6 f, 1.7×10-6 f, 5.9×10-6 f, and two 9.4×10-6 f in series. 1) what is the equivalent capacitance of all five? c =

Answer 1

All of them are 10^-6. You can put that in at the end because it is a common factor.

1/c = 1/0.6 + 1/1.7 + 1/5.9 + 1/9.4 + 1/9.4
1/c = 2.638
2.638 c = 1
c = 1/2.638
c = 0.379

So the actual capacitance is 0.379 * 10^-6 <<<<<=====
At first glance, you might observe that this answer is smaller than all the rest. That's as it should be. Capacitances when put in series are always smaller than the smallest one you start with.