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4 years ago

Blake is finding 4/5 divided by 6/7. Find his mistake if he got 30/28 or 1 1/4

1 answer:

6 0

$\bf \cfrac{4}{5}\div \cfrac{6}{7}\implies \stackrel{\bigotimes}{\cfrac{5}{4}}\cdot \cfrac{6}{7}\implies \cfrac{30}{28}~\hfill \cfrac{4}{5}\div \cfrac{6}{7}\implies\cfrac{4}{5}\cdot \stackrel{\checkmark}{\cfrac{7}{6}}\implies \cfrac{28}{30}\implies \cfrac{14}{15}$

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The area of a rectangular field is 2275 m2. The field is enclosed by 200 m of fence. What are the dimensions of the field?

AURORKA [14]

So it is enclosed by 200 m of fence
perimiter=200 m
it is a rectangle to
p=legnth+legnth+width+width or
p=l+l+w+w or
p=2l+2w or
p=2(l+w)
so
p=200
200=2(l+w)
divide both sides by 2
100=l+w
area=l times w
area=2275
lw=2275
l+w=100
combine and solve
l+w=100
subtract w
l=100-w
subisutute 100-w for l in other eqution
(100-w)(w)=2275
distribute
-w^2+100w=2275
add (w^2-100w) to both sides
0=w^2-100w+2275
factor
find what 2 numbers add up to -100 and multiply to get 2275
guess (or factor 2275 and find factors that add up to -100)
figure out that they are -65 and -35
0=(w-65)(w-35)
set each to zero
0=w-65
0=w-35

solve for w
w=65 or 35
65>35 so
65 m=legnth
35 m=width

4 0

4 years ago

Mason will use a 1/3 gallon pitcher to fill an empty 3/4 gallon water jug. How much water will he need in order to completely fi

kirza4 [7]

Answer:

It's 1/2 I found this out by subtracting 3/4 - 1/3= 5/12 and if you put that into a decimal it would be .41. So that 1/4= .25 and 1/2= .50. You could figure out that it’s closed to 1/2.

3 0

3 years ago

Read 2 more answers

Solve the system of linear equations.

icang [17]

Answer: The set does not have a solution

Step-by-step explanation:

Adding Equations 1 & 3 we get 5x = 7. This gives x = 7/5

Putting this value of x in eq. 2 we get

-2y + 2z = -1-(7/5) or

2y - 2z = 12/5 or 5y - 5z = 6

Multiplying eq. 1 by 2 we get

4x + 2y - 2z = 6

adding this with eq. 2 we get 5x = 5 or x = 1

As the common solution for x from equations 1&3 does not satisfy eq. 1&2 it comes out that the three equations do not have a common solution.

Same can be verified by using different sets of two equations also.

7 0

4 years ago

HELP PLEASE,<br><br> Part a of the question was posted earlier on.

Elanso [62]

$\bf \lim\limits_{x\to 6}~\cfrac{x^2+x+42}{x-6}\implies \lim\limits_{x\to 6}~\cfrac{(x+7)(x-6)}{(x-6)}\implies \lim\limits_{x\to 6}~x+7
\\\\\\
\lim\limits_{x\to 6}~(6)+7=13
\\\\\\
\textit{since the original equation holds for all, }x\ne 6,\textit{ then it approaches}\\
\textit{the same limit as }x+7$

3 0

3 years ago

Weight of a rock: In a geology course, students are learning to use a balance scale to accurately weigh rocks. One student plans

statuscvo [17]

Answer:

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

Step-by-step explanation:

What is Confidence Interval?

The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.

The confidence interval is given by

$CI = \bar{x} + t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\$

Where $\bar{x}$ is the mean weight $\sigma$ is the standard deviation $t_{\alpha/2}$ is the critical value from t-table and n is the sample size.

The term $t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } )$ is known as margin of error.

As the sample size is decreased the corresponding margin of error increases which results in wider confidence interval which means smaller precision.

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

We can say with 95% confidence that the true mean weight of the rock is within the interval of (25.2, 29.1).

7 0

3 years ago