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skad [1K]
2 years ago
9

On the first math exam, 16 students received an A grade. On the second math exam

Mathematics
1 answer:
Nady [450]2 years ago
6 0

Answer:

0 percent because all the students got an A grade.

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Kesha rode her bike 12 miles from home to the store. She rode her bike back towards home from the store for 8 miles then walked
stellarik [79]

Answer:

0 Kesha is already home 8+4 is 12 and it's 12 miles from the store to her house .-.

Step-by-step explanation:

5 0
3 years ago
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Suppose you are playing a game of Uno and you must draw two cards from the deck. An Uno deck contains
Elina [12.6K]

Answer:

hatdog jdudhsisbsn

Step-by-step explanation:

jsysvysbd

7 0
2 years ago
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Write an equation for a line that is parallel to 2x+5y=15 and passes through the point (-10, 3)​
Lyrx [107]

Answer:

The equation of the line is,

y =  -  \frac{2}{5} x - 1

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

2x + 5y = 15

5y = 15 - 2x

y = 3 -  \frac{2}{5} x

y =   - \frac{2}{3} x + 5

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

y =   - \frac{ 2}{5}x + b

let \: x =  - 10,y = 3

3 =  -  \frac{2}{5} ( - 10) + b

3 = 4 + b

3 - 4 = b

b =  - 1

3 0
3 years ago
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Find a degree 3 polynomial with real coefficients having zeros 4 and 2i and a lead coefficient of 1. Write P
iren2701 [21]

Answer:

x^2 - 2xi - 4x +8i

Step-by-step explanation:

(x -4) (x -2i) (x+2i)

4 0
3 years ago
The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV
JulijaS [17]

Answer:

\frac{dT}{dt}=3.78^{\circ}K/min

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}

What we have to do is the derivative of a product:

\frac{d(PV)}{dt}=P\frac{dV}{dt}+V\frac{dP}{dt}

Substituting, we have:

\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

\frac{dT}{dt}=\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}=\frac{(8atm)(0.16L/min)+(13L)(0.14atm/min)}{(10mol)(0.0821Latm/mol^{\circ}K)}

And then just calculate:

\frac{dT}{dt}=3.78^{\circ}K/min

6 0
2 years ago
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