What terms govern the length of this side?The basic rule of the triangle.First side length must be less than the sum of the other two sides.So to find X we must take the largest side of the triangles and compare them with amounts from other sides.

5+x>12
8+x>20 and it's system

x>7
x>12
general solution is x>12
<span>The least possible integral is 13.

PS: It's may be </span>yet 12, but in this case, triangle BCD become segment.

6 0

3 years ago

Solve for b in the literal equation a b = c.

Evgesh-ka [11]

Answer:

b = $\frac{c}{a}\\$

Step-by-step explanation:

divide both sides by a

bring the a over to the other side and put it under the c as the opposite of times is divide

7 0

3 years ago

Which term could be put in the blank to create a fully simplified polynomial written in standard form?

Monica [59]

Answer: It’s A on edge

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How do I solve this ?

timofeeve [1]

Answer:

$\large\boxed{\{4,\ 7,\ 10\}}$

Step-by-step explanation:

$X\ \cup\ Y\\\text{The union of a collection of sets is the set of all elements in the collection.}\\\\X\ \cap\ Y\\\text{The intersection}\ X\cap Y\ \text{of two sets X and Y is the set that contains}\\\text{all elements of X that also belong to Y, but no other elements.}\\\\A'\\\text{When A is a subset of a given set U, the absolute complement A}\\\text{is the set of elements in U, but not in A.}$

$U=\{3,\ 4,\ 5,\ 6,\ 7,\ 8,\ 9,\ 10\}\\A=\{4,\ 6,\ 8\}\\B=\{3,\ 4,\ 7,\ 10\}\\C=\{3,\ 5,\ 9\}\\\\A\ \cup\ B=\{4,\ 6,\ 8\}\ \cup\ \{3,\ 4,\ 7,\ 10\}=\{3,\ 4,\ 6,\ 7,\ 8,\ 10\}\\C'=\{3,\ 4,\ 5,\ 6,\ 7,\ 8,\ 9,\ 10\}-\{3,\ 5,\ 9\}=\{4,\ 6,\ 7,\ 8,\ 10\}\\B\ \cap\ C'=\{3,\ \b4,\ \b7,\ \b1\b0\}\ \cap\ \{\b4,\ 6,\ \b7,\ 8,\ \b1\b0\}=\{\b4,\ \b7,\ \b1\b0\}\\\\(A\ \cup\ B)\ \cap\ (B\ \cap\ C')=\{3,\ \b4,\ 6,\ \b7,\ 8,\ \b1\b0\}\ \cap\ \{\b4,\ \b7,\ \b1\b0\}=\{\b4,\ \b7,\ \b1\b0\}$

6 0

3 years ago