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vfiekz [6]
2 years ago
15

When you make the circle bigger or smaller, which number of the standard equation for the circle centered at the origin changes?

Mathematics
2 answers:
Len [333]2 years ago
6 0
I think the correct answer from the choices listed above is option C. <span>When you make the circle bigger or smaller, it is the radius of the standard equation for the circle centered at the origin changes. Hope this answers the question. Have a nice day.</span>
Artist 52 [7]2 years ago
3 0

Answer:

Option (C) is correct,

when we make the circle bigger or smaller we will change its radius.

Step-by-step explanation:

 A circle with standard equation,  (x-h)^2 + (y-k)^2 = r^2 where (h, k) is the center and "r"  being the radius.

We have to determine out of given options which number of the standard equation for the circle centered at the origin changes when you make the circle bigger or smaller.

Given :  Circle centered at the origin then (h , k ) becomes (0, 0)

Thus, equation of circle becomes,

(x-h)^2 + (y-k)^2 = r^2

Substitute h = 0  and  k = 0  , we get,

\Rightarrow (x-0)^2 + (y-0)^2 = r^2

 \Rightarrow x^2 + y^2 = r^2

Since, x and y coordinates depends on radius.

Thus when we make the circle bigger or smaller we will change its radius.

Thus, option (C) is correct,


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2 years ago
Whats the cost of each vegetable if 5 squash and 2 zucchini is $1.32​
alex41 [277]

Answer:

Step-by-step explanation:

 

We first need to define a couple of variables.  Let s = the cost of 1 squash and z = the cost of 1 zucchini.

 

Now lets translate the words into algebra:

 

"The cost of 5 squash and 2 zucchini is $1.32"  ===>  5s  +  2z  =  1.32

 

"Three squash and 1 zucchini cost $0.75"  ===>   3s  +  z  =  0.75

 

There are several ways to solve systems of equations.  Let's use substitution.  We can find what z equals in terms of s by manipulating the second equation:

 

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-3s                 -3s

------------     -------------

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Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:

 

 5s + 2(-3s + 0.75) = 1.32

 

Can you handle it from here?

 

(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)

3 0
3 years ago
I really need help would please like help thanks
ASHA 777 [7]
Hey there!

A reciprocal might be an unfamiliar vocab word, but the concept is really quite simple.

It's just a flipped fraction! Multiplying the flipped fraction by it's reciprocal gets you one, and that's how you check your answer.

So we have:

Reciprocal of 9/10 is 10/9, because 9/10 times 10/9 = 90/90 = 1

Reciprocal of 1/11 is 11/1, because 1/11 times 11/1 = 11/11 = 1

Reciprocal of 10(remember, it's 10/1) is 1/10, because 10/1 times 1/10 = 10/10 = 1

Hope this helps!
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Answer:

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