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ololo11 [35]
3 years ago
6

HURRY PLEASEWhat is the end behavior of the polynomial function?

Mathematics
1 answer:
strojnjashka [21]3 years ago
7 0
C x to positive infinity and y to negative infinity
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Keisha has a straightedge and a compass, but noprotractor. What kind of angle can Keisha draw exactly with only these tools?
sukhopar [10]
<span>Straight (it's a straight line!), full rotation (a circle), but nothing else since you can't measure the exact angle of it</span>
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What is the multiplicative inverse of 2 1/2?<br><br> A) 2/3<br> B) 2/5<br> C)2
zheka24 [161]
If you get rid of the whole number in that fraction, you will have 3/2.
So the opposite of that would be 2/3.
I believe the answer is 2/3.
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Question 5: The volume of each cube is given.
san4es73 [151]

Answer:

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Which of the following is considered to be an accrued expense
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Answer:where

Step-by-step explanation:

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For the piecewise function, find the values h( - 6), h(0), h(5), and h(9).- 5x – 13, for x &lt; -3h(x) = { 5, for - 35x&lt;5for
sleet_krkn [62]

Given the piecewise function h(x):

h(x)=\begin{cases}-5x-13,x

-When x is less than "-3", h(x)=-5x-13

-When x is between -3 and 5, h(x)=5

-When x is greater than or equal to 5, h(x)=x+1

1) For h(-6), this notation indicates that you have to determine the value of h(x) when x=-6

-6 is less than -3, which means that for this value of x, the function has the following shape

h(x)=-5x-13

Replace the expression with x=-6 and calculate the corresponding value of x:

\begin{gathered} h(-6)=-5(-6)-13 \\ h(-6)=30-13 \\ h(-6)=17 \end{gathered}

2) For h(0), you have to determine the value of h(x) when x=0. Zero is between -3 and 5, for this value of x, the function h(x) has the following shape:

h(x)=5

This equation represents a horizontal line, which means that for every value within the interval of definition -3≤x<5, the function always has the same value h(x)=5

We can conclude that:

h(0)=5

3) For h(5), you have to determine the value of h(x) for x=5, for values of x greater than or equal to 5, h(x) has the following shape:

h(x)=x+1

Replace the expression with x=5 and calculate the corresponding value of h(x):

\begin{gathered} h(5)=5+1 \\ h(5)=6 \end{gathered}

4) For h(9), you have to determine the value of h(x) when x=9, 9 is greater than 5, for this value of x, the function has the following shape:

h(x)=x+1

Replace the expression with x=9, and calculate the corresponding value of h(x):

\begin{gathered} h(9)=9+1 \\ h(9)=10 \end{gathered}

So, to sum up:

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5 0
1 year ago
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