All categories

3 years ago

Juliette forgot to study for a test. Of the 150 questions on the test, she answered only 48% correctly. How many questions did

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

I think the answer would be 72:)

Kamila [148]3 years ago

5 0

Answer:

Juliette answered 72 questions correctly

Step-by-step explanation:

48% of 150 = 72

You might be interested in

Can you help me pleaseeeeeew

Lera25 [3.4K]

Answer:

<h2>The answer is A 14.6</h2>

Step-by-step explanation:

the diameter is twice the length of the radius soooo 7.3x2=14.6

making the answer A

4 0

3 years ago

A polygon with ten sides is called a _____.

IceJOKER [234]

The answer is decagon

4 0

3 years ago

Read 2 more answers

The average height of 18-year-old American women is 64.2 inches. You wonder whether the mean height of this year's female gradua

Anna007 [38]

Answer:

Step-by-step explanation:

Wanna chat add me as a friend OR COME TO SANP (ADAMBELAL839)

6 0

3 years ago

04 Name the

kirill [66]

Answer:

<h3>integers integers OK ok ok ok ok ok ok</h3>

5 0

3 years ago

A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

3 years ago