Answer:
15.47 gallons
Explanation:
The pumps remove the oil at the rate modelled by
R(t) = 2 + cos(πt / 11) in gallon per hour
The oil removes in 6hours period is given by integral of R(t)
from t = 0 to t = 6

![Q = [2t + \frac{sin(\frac{\pi t}{11}) }{\frac{\pi }{11} } ]_0^6](https://tex.z-dn.net/?f=Q%20%3D%20%5B2t%20%2B%20%5Cfrac%7Bsin%28%5Cfrac%7B%5Cpi%20t%7D%7B11%7D%29%20%7D%7B%5Cfrac%7B%5Cpi%20%7D%7B11%7D%20%7D%20%5D_0%5E6)
![Q = [2(6) + \frac{11}{\pi } sin(\frac{6\pi }{11}) ] - [0 + \frac{11sin (0)}{\pi } ]](https://tex.z-dn.net/?f=Q%20%3D%20%5B2%286%29%20%2B%20%5Cfrac%7B11%7D%7B%5Cpi%20%7D%20sin%28%5Cfrac%7B6%5Cpi%20%7D%7B11%7D%29%20%5D%20-%20%5B0%20%2B%20%5Cfrac%7B11sin%20%280%29%7D%7B%5Cpi%20%7D%20%5D)
![Q = [12 + \frac{11}{\pi } (0.9898)]\\\\Q = 12 + 3.465694\\\\Q = 15.465694\\\\Q = 15.47 gallons](https://tex.z-dn.net/?f=Q%20%3D%20%5B12%20%2B%20%5Cfrac%7B11%7D%7B%5Cpi%20%7D%20%280.9898%29%5D%5C%5C%5C%5CQ%20%3D%2012%20%2B%203.465694%5C%5C%5C%5CQ%20%3D%2015.465694%5C%5C%5C%5CQ%20%3D%2015.47%20gallons)
259200 seconds in 3 days and 136800 seconds in 38 hours
Answer:
based on theory, its gravitational pull on the other planets will weaken and they'll drift farther away.
The answer is B because there is a total of 10N to the right and 5 to the left, 10-5=5
False.
Unweathered rock that underlies soul is known as bedrock.