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3 years ago

What is the equations to prove the answer is A?

Physics

1 answer:

Pepsi [2]3 years ago

7 0

Explanation:

Let's say your mass is M, the ball's mass is m, and the ball's speed is v. Let's say your final speed is V.

Momentum is conserved. If you catch the ball, your speed is:

mv = (m + M)V

V = mv / (m + M)

If you deflect the ball, your speed is:

mv = MV + m(-v)

V = 2mv / M

To compare these, we need the common denominator.

If you catch the ball:

V = mMv / (M (m + M))

If you throw the ball:

V = 2m(m + M)v / (M (m + M))

Comparing the numerators, we can see M < 2(m + M), so catching the ball results in a lower speed.

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When a sinusoidal wave with speed 20 m/s , wavelength 35 cm and amplitude of 1.0 cm passes, what is the maximum speed of a point

vova2212 [387]

To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion

From the definition we know that the frequency can be expressed as

$f = \frac{v}{\lambda}$

Where,

$v = Velocity \rightarrow 20m/s$

$\lambda = Wavelength \rightarrow 35*10^{-2}m$

Therefore the frequency would be given as

$f = \frac{20}{35*10^{-2}}$

$f = 57.14Hz$

The frequency is directly proportional to the angular velocity therefore

$\omega = 2\pi f$

$\omega = 2\pi *57.14$

$\omega = 359.03rad/s$

Now the maximum speed from the simple harmonic movement is given by

$V_{max} = A\omega$

Where

A = Amplitude

Then replacing,

$V_{max} = (1*10^{-2})(359.03)$

$V_{max} = 3.59m/s$

Therefore the maximum speed of a point on the string is 3.59m/s

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3 years ago

A tangent line drawn on a velocity-time graph has a rise of 19 m/s and a run of 4.0 m/s. How large is the acceleration? What typ

klemol [59]

Answer:

Acceleration = 4.8 m/s²

Explanation:

Given:

Change in velocity = 19 m/s

Change in time = 4 s

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Positive acceleration

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2 years ago

To protect her new two-wheeler, Iroda Bike

goldfiish [28.3K]

Answer:

The length of chain she is allowed is 1.169 ft

Explanation:

The given parameters are;

The linear density of the chain = 0.83 lb/ft

The weight limit of the chain she wants = 1.4 lb

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Therefore, in order to keep the chain below 1.4 lb, we have;

Linear density = Weight/length

Therefore;

The maximum length she wants = Weight/(Linear density)

Which gives;

The maximum length she wants = 1.4 lb/(0.83 lb/ft) =1.169 ft

Therefore;

The length of chain she is allowed = 1.169 ft.

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2 years ago

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andreyandreev [35.5K]

Answer:

the answer choice is B

Explanation:

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2 years ago

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Answer:

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