Does the mass change how a bouncy ball bounces

2 answers:

6 0

The more mass an object has, the more kinetic energy it has when dropped, due to gravity. ... If the force of impact is too great for the ball to absorb, it may collapse and lose its bounce as the energy is dissipated in a different manner.

Allushta [10]3 years ago

5 0

Answer:

hiii what's up. and good morning hyd

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A bicycle rider has a speed of 20.0 m/s at a height of 60 m above sea level when he begins coasting down hill. Sea level is the

IRINA_888 [86]

Answer:

The rider's speed will be approximately 35 m/s

Explanation:

Initially the rider has kinetic and potential energy, and after going down the hill, some of the potencial energy turns into kinetic energy. So using the conservation of energy, we have that:

$kinetic_1 + potencial_1 = kinetic_2 + potencial_2$

The kinetic and potencial energy are given by:

$kinetic = mass * speed^2 / 2$

$potencial = mass * gravity * height$

So we have that:

$m*v^2/2 + mgh = m*v'^2/2 + mgh'$

$20^2/2 + 9.81*60 = v'^2/2 + 9.81*18$

$v'^2/2 + 176.58 = 788.6$

$v'^2/2 = 612.02$

$v'^2 = 1224.04$

$v' = 34.99\ m/s$

So the rider's speed will be approximately 35 m/s

8 0

3 years ago

When resistance force is increased on a lever which of the following happens to the effort force?

Sauron [17]

When resistance force on a lever increases, nothing happens automatically.
But if you want to keep lifting the load, then YOU must increase the force of
your effort in order to make it happen.

8 0

3 years ago

HELP !! Maura is deciding which hose to use to water her outdoor plants. Maura noticed that the water coming out of her garden h

MA_775_DIABLO [31]

THE GREEN HOSE:
Define the (x,y) coordinate at a height of 4 feet up from the ground to match where Majra is holding the green hose.
This means that the equation for the green hose is of the form
y = a(x - h)² + 4 (1)

Because water from the green hose lands on the ground 10 feet from where Majra is standing, therefore
y(10) = -4 (2)

Because the curve passes through (0,0), therefore
ah² + 4 = 0
ah² = - 4 (3)

To satisfy (2), obtain
a(10 - h)² + 4 = -4
a(10 - h)² = - 8 (4)

Divide (3) by (4).
h²/(10-h)² = 1/2
2h² = (10 - h)² = 100 - 20h + h²
h² + 20h - 100 = 0

Solve with the quadratic formula.
x = 0.5[-20 +/- √(8400)] = 4.142, - 24.142
Reject the negative solution.
The vertex is at (4.142, 4).

From (3), obtain
a = -4/4.142² = -0.2332

The equation for the green hose is
y = 0.2332(x - 4.142)² + 4

THE RED HOSE
The red hose has a vertex at (3,7), according to the equation y = -(x-3)² + 7.

A graph of y(x) for both hoses is shown in the attached figure.

Answers:
a. The red hose will throw the water higher.

b. The equation for the green hose is
y = -0.2332(x - 4.124)² + 4,
with the origin at a height of 4 feet above ground level.

c. The domain for the green hose that makes sense is 0 ≤ x ≤ 10 feet.
The corresponding range is -4 ≤ y ≤ 4 feet.