The nth term of the geometric sequence is:
an=ar^(n-1)
where
a=first term
r=common ratio
n=nth term
from the question:
120=ar(3-1)
120=ar^2
a=120/(r^2)....i
also:
76.8=ar^(5-1)
76.8=ar^4
a=76.8/r^4.....i
thus from i and ii
120/r^2=76.8/r^4
from above we can have:
120=76.8/r²
120r²=76.8
r²=76.8/120
r²=0.64
r=√0.64
r=0.8
hence:
a=120/(0.64)=187.5
therefore the formula for the series will be:
an=187.5r^0.8
Answer:
9
Step-by-step explanation:
3-sqrt(x)=0 should be rewritten as 3 = sqrt(x) or sqrt(x) = 3.
To obtain the value of x that satisfies this equation, square both sides:
x = 3^2, or x = 9.
($0.45 x 7.2) + ($0.45 x 6.8) <span>
= $3.24 + $3.06
= $6.30
answer
</span><span>$6.30</span><span>
</span>
Answer:
71
Step-by-step explanation:
(73)-2 is equivalent to 71
What textbook is it the texas math textbook or wat