What is the slope of a line that contains points (3, 10) and (3, -2)?

Mathematics

2 answers:

marishachu [46]3 years ago

7 0

Slope is y2-y1/x2-x1

Let’s make the point (3,10) our x1 and y1 and let’s make (3,-2) our x2 and y2

-2-10/3-3

-12/0 = undefined

The slope is undefined. If it were to be 0/-12, the answer would be 0. If any number were to be divided by 0, it would be undefined.

Hope I helped!

Nikitich [7]3 years ago

4 0

To find the slope, using the coordinates, you will plug them into the slope formula.

Slope formula: $\frac{y^{2} -y^{1} }{x^{2}-x^{1}}$

You plug in the 2nd Y-cordinate in y2 and the 1st y-coordinate in y one. Then you do the same thing for the-x coordinates. Plug in the 2nd x-cordinate in x2, and 1st x-cordinate in x1.

You plug in -2 and 10 in the y2 and y1, respectively. Also, you plug in 3 and 3 in x2 and x1 respectively.

The equation you're going to get after plugging in is:

$\frac{-2-10}{3-3}$

Then you solve the equation. You subtract -2 to 10, it will be the same as -2 + -10, you would get -12. Then for the bottom, 3-3 will end up as 0

You will end up with:

$\frac{-12}{0}$

The answer you will get is undefined after completing all of the steps with the slope formula. The reason why it's undefined is because with the fraction ( $\frac{-12}{0}$ ) you rise (up) over run (right). And the -12 would be your rise, and 0 would be your run. Since the run value is 0, you're only going to go up or down in a straight line. And you can't define what the slope is.

The slope of the line is undefined.

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3 0

2 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$