Answer:sorry I can't see that
Step-by-step explanation:
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.
Similarly, we have
Now, to find the lengths of the diagonals,
So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
Since HLI and HLG are complementary angles (add together to make 90 degrees), you can set them up in the equation (25m + 22) + (9m) = 90.
25m + 22 + 9m = 90 add like numbers
34m + 22 = 90 subtraction property
34m = 68 divide
m = 2
substitute m = 2 into the equation got angle HLG (25m + 22)
25(2) + 22
50 + 22
HLG = 72
Answer: 1
13pi/2 can be simplified onto 6 pi/2, so it goes around the unit circle 6 times and left with pi/2. the coordinates of pi/2 is (0,1). the trigonometric function sin is y/r. since r is always 1 on the unit circle, the answer is the y value, in this case it is 1.
Answer:
x equals -7 and x equals 5 our function is discontinuous
Step-by-step explanation:
x^2+7x-5x-35=0
x(x+7)-5(x+7)=0
(x+7)(x-5)=0
(x+7)=0\text{ or }(x-5)=0
x=-7\text{ or }x=5