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3 years ago

15

Graph the equation by plotting points. x=6

1 answer:

Margaret [11]3 years ago

4 0

Your line will be vertical through the line 6 on the x axis, points- (6,0), (6,1), (6,2) etc..

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What are the whole number from 1/3 to 30

kobusy [5.1K]

1, 2, 3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30.

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3 years ago

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Factor out in steps. . 3p^2-2p-5.

inn [45]

$3p^2-2p-5=3p^2-5p+3p-5=p(3p-5)+1(3p-5)\\\\=\boxed{(3p-5)(p-1)}$

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3 years ago

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The coordinates of the vertices of parallelogram RMBS are R(–4, 5), M(1, 4), B(2, –1), and S(–3, 0). Using the diagonals, prove

REY [17]

To prove a rhombus you need to show that the sides are congruent and the diagonals are perpendicular.

Sides:

$d_{RM}=\sqrt{(-4-1)^2+(5-4)^2}$

$=\sqrt{(-5)^2+(1)^2}$

$=\sqrt{25+1}$

$=\sqrt{26}$

$d_{MB}=\sqrt{(1-2)^2+(4+1)^2}$

$=\sqrt{(-1)^2+(15)^2}$

$=\sqrt{1+25}$

$=\sqrt{26}$

$d_{BS}=\sqrt{(2+3)^2+(-1-0)^2}$

$=\sqrt{(5)^2+(-1)^2}$

$=\sqrt{25+1}$

$=\sqrt{26}$

$d_{SR}=\sqrt{(-3+4)^2+(0-5)^2}$

$=\sqrt{(1)^2+(-5)^2}$

$=\sqrt{1+25}$

$=\sqrt{26}$

$\overline{RM}$ ≅ $\overline{MB}$ ≅ $\overline{BS}$ ≅ $\overline{SR}$

Diagonals:

Use the slope formula: $m=\dfrac{y_2-y_1}{x_2-x_1}$

$m_{RB}=\dfrac{5+1}{-4-2}$

$=\dfrac{6}{-6}$

= -1

$m_{MS}=\dfrac{4-0}{1+3}$

$=\dfrac{4}{4}$

= 1

Slopes are opposite reciprocals so they are perpendicular.

***************************************************************************

All of the sides are congruent and the diagonals are perpendicular so RMBS is a rhombus.

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4 years ago

The volume (V) of water stored in an open tank varies due to evaporation as

Elena L [17]

75 is your answer

Hope this helped

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3 years ago

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It says solution to the equation as a decimal q-1.8+1.8=14+1.8

Zielflug [23.3K]

Q-1.8+1.8=14+1.8= Q=15.8 hope this helps

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3 years ago