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Georgia [21]
3 years ago
8

Solve 3^n=5. How to solve n?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

\huge\boxed{n=\log_35}

Step-by-step explanation:

3^n=5\Rightarrow\log_33^n=\log_35\qquad\text{use}\ \log_ab^n=n\log_ab\\\\n\log_33=\log_35\qquad\text{use}\ \log_aa=1\\\\\boxed{n=\log_35}

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What's an equivalent equation for -5(3-2x)
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