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son4ous [18]
3 years ago
6

It is known that the point P(−9, 18) belongs to the graph of the function y= k/x . Find k.

Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer:

-162

Step-by-step explanation:

y = k / x

Plug in values.

18 = k / -9

Solve for k by multiplying both sides by -9.

k = -162

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<u>well 8 divided by 4 is 2 and 11-8+2 is 5 and 5 times 4 is 20 so 20 is the answer

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in a class of 30 students the highest score in physics test was 98 and the lowest was 35 what was the range?​
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5 0
2 years ago
(06.01) In the below system, solve for y in the first equation. x + 3y = 6 2x − y = 10 one thirdx + 2 negative one thirdx + 6 −x
NISA [10]

we have that

x + 3y = 6 -------> first equation

2x − y = 10


x + 3y = 6-----> substract x both sides

-x+x+3y=6-x

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y=(6-x) /3

y=2-(x/3)

y=-(x/3)+2

therefore


the answer is

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5 0
3 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
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