1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zvonat [6]
3 years ago
6

Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of

the element.
Mathematics
1 answer:
Nata [24]3 years ago
7 0
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
You might be interested in
Find all the real square roots of 0.0064
LenKa [72]
√64 = 8

64÷1000 = 0.0064

8÷1000=0.0008

√0.0064 = 0.0008
5 0
3 years ago
Read 2 more answers
A recycling bin is in the shape of a rectangular prism has a volume of 960 inches is the base area of the recycling bin is 32 in
anygoal [31]
30 inches because 32x30=960 and the formula being used is V=bh.
3 0
2 years ago
Read 2 more answers
A right circular cone of height h and base radius r has total surface area S consisting of its base area plus its side area, lea
Yuki888 [10]

Answer:

gfgj

Step-by-step explanation:

5 0
3 years ago
Really need help guys
DaniilM [7]
Sorry but can we get a better shot of the paper can barley see it
3 0
3 years ago
The number of employees for a certain company has been decreasing each year by 3%. If the company currently has 810 employees an
8090 [49]

Answer:

219 employees

Step-by-step explanation:

3% of decreasing rate of employees per year is calculated thus:

3\% \: of \: 810 \: employees

=  \frac{3}{100}  \times 810

= 24.3 \: employees \: per \: year

In 9 years,

= 24.3 \times 9

= 218.7 = 219 \: employees

Therefore, the number of employees for a certain company where decreasing rate of employees is 3% and continued to decrease for 9 years; and 810 employees are currently working is 219 employees. By implication, 810 + 219 = 1029 employees were working in the company 9 years ago.

6 0
2 years ago
Other questions:
  • If a new car has 2 transmission​ types, 3 vehicle​ styles, 2 option​ packages, 9 exterior color​ choices, and 2 interior color​
    10·1 answer
  • Calculate the difference between the 1990-1997 average blue crab population and the 1998-2009 average blue crab population predi
    8·1 answer
  • 5?10 5 5, dot, 10, start superscript, 5, end superscript is how many times as large as 1\cdot10^51?10 5 1, dot, 10, start supers
    15·1 answer
  • Jessie has a piece of wood that is 8 feet long. he needs to cut pieces that are 7/8 of a foot long. how many pieces will he b ab
    10·2 answers
  • What is the slope of the line when the line crosses through (4,5)
    5·1 answer
  • Can you help me in rule? <br><br> I am doing it right?
    15·1 answer
  • How does the mean compare to the median? How do the values of 7 and 9 affect these measures of center?
    13·1 answer
  • Find the volume of a right circular cone that has a height of 3.2m and a base with a radius of 14.1m. Round your answer to neare
    10·1 answer
  • Sam buys a DVD player for $55. 95 and it is on sale for 40% off regular price. How much money will same save
    6·1 answer
  • A) ¿Cuántas veces contiene la unidad base a la correspondiente del prefijo deci?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!