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zvonat [6]
3 years ago
6

Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of

the element.
Mathematics
1 answer:
Nata [24]3 years ago
7 0
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
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Step-by-step explanation:

Let x be the number.

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2 years ago
On the last day of the fiscal year, a co-worker asks you to cut a check for $2,000 as a miscellaneous expense for supplies in or
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Answer:

A. No, Should not in any way write the check today and neither record the expense or even write the check tomorrow.

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Step-by-step explanation:

A. Based on accounting principle every debit entry must have a corresponding credit entry which means that in a situation where a check is been cut today for miscellaneous expense and for supplies the Miscellaneous expense account should be debited while the bank account should as well be credited based on the double entry principle because if not so the current year net income will wrongly shows and be higher with the amount of $2,000.

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4 0
3 years ago
the sum of three consecutive even integers is 6 subtracted from 4 times the middle number. Find the 3 numbers
anygoal [31]

Answer:

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8 0
3 years ago
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larisa [96]

Answer:

Right and isosceles

Step-by-step explanation:

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6 0
2 years ago
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